Java中那些不得不说的坑
程序员文章站
2022-05-04 19:54:48
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看看下面这段代码跟你想的结果一样吗?
Integer a =127;
Integer b = 127;
System.out.println(a==b);//true
Integer a1 = 128;
Integer b1 = 128;
System.out.println(a1==b1);//false
为什么会是这样的结果,我们反编译.class文件看看
Integer a = Integer.valueOf(127);
Integer b = Integer.valueOf(127);
System.out.println(a == b);
Integer a1 = Integer.valueOf(128);
Integer b1 = Integer.valueOf(128);
System.out.println(a1 == b1);
其实是Integer作者在写这个类时,为了避免重复创建对象,对一定范围的Integer做了缓存,如果该值没有在该范围内则new一个新对象返回,从源码中可以看到如下代码:
public static Integer valueOf(int i) {
if (i >= IntegerCache.low && i <= IntegerCache.high)
return IntegerCache.cache[i + (-IntegerCache.low)]; //i如果在该范围内直接返回缓存值
return new Integer(i);
}
IntegerCache 是Integer 类的静态内部类,再来看看IntegerCache的实现
private static class IntegerCache {
static final int low = -128;
static final int high;
static final Integer cache[];
static {//当类被载入到java虚拟机是进行缓存创建
// high value may be configured by property
int h = 127;
String integerCacheHighPropValue =
sun.misc.VM.getSavedProperty("java.lang.Integer.IntegerCache.high");
if (integerCacheHighPropValue != null) {
try {
int i = parseInt(integerCacheHighPropValue);
i = Math.max(i, 127);
// Maximum array size is Integer.MAX_VALUE
h = Math.min(i, Integer.MAX_VALUE - (-low) -1);
} catch( NumberFormatException nfe) {
// If the property cannot be parsed into an int, ignore it.
}
}
high = h;
cache = new Integer[(high - low) + 1];
int j = low;
for(int k = 0; k < cache.length; k++)
cache[k] = new Integer(j++);
// range [-128, 127] must be interned (JLS7 5.1.7)
assert IntegerCache.high >= 127;
}
private IntegerCache() {}
}
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