myeclipse通过数据表生成jpa或hibernate实体
程序员文章站
2022-05-04 16:23:32
...
就是说,如果你已经有了数据库表,那么你又不想手工书写jpa或hibernate实体(要谁都不想,还要自己写那么一大堆的注解),myeclipse能够帮助你自动生成。
1、首先你需要创建一个jpa项目:
如图在普通项目上点右键添加
2、打开生成工作环境
3、创建数据库连接
因为,myeclipse也要连接数据库获取表结构
4、填写连接信息
5、打开表列表,选择导出模式
6、保存导出实体工程选择
(这一步需要第1步的操作,否则,没有可选工程)
现在就生成了entity,如:
package com.partner4java.entity;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import static javax.persistence.GenerationType.IDENTITY;
import javax.persistence.Id;
import javax.persistence.Table;
/**
* User entity. @author MyEclipse Persistence Tools
*/
@Entity
@Table(name = "user", catalog = "hello_world")
public class User implements java.io.Serializable {
// Fields
private Integer id;
private String username;
private String password;
private String address;
// Constructors
/** default constructor */
public User() {
}
/** minimal constructor */
public User(String username, String password) {
this.username = username;
this.password = password;
}
/** full constructor */
public User(String username, String password, String address) {
this.username = username;
this.password = password;
this.address = address;
}
// Property accessors
@Id
@GeneratedValue(strategy = IDENTITY)
@Column(name = "id", unique = true, nullable = false)
public Integer getId() {
return this.id;
}
public void setId(Integer id) {
this.id = id;
}
@Column(name = "username", nullable = false, length = 20)
public String getUsername() {
return this.username;
}
public void setUsername(String username) {
this.username = username;
}
@Column(name = "password", nullable = false, length = 20)
public String getPassword() {
return this.password;
}
public void setPassword(String password) {
this.password = password;
}
@Column(name = "address", length = 20)
public String getAddress() {
return this.address;
}
public void setAddress(String address) {
this.address = address;
}
}
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