欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

Python学习之函数及流程控制

程序员文章站 2022-05-04 13:01:25
...
这篇文章主要为大家详细介绍了Python学习之函数及流程控制,具有一定的参考价值,感兴趣的小伙伴们可以参考一下

#猜年龄大小,用户最多猜三次

age = 50
 
i = 0
 
while i < 3:
 
    guess_age = int(input("Please input your answer:"))
 
    if guess_age > age:
 
        print("too big...try again please")
 
    elif guess_age < age:
 
        print("too small...try again please")
 
    else:
 
        print("You guessed it!")
 
        break
 
    i += 1
 
    if i == 3:

#猜年龄,每隔三次询问是否继续玩

age = 50
 
for i in range(1,100):
 
    guess_age = int(input("Please input your answer:"))
 
    if guess_age > age:
 
        print("too big...try again please")
 
    elif guess_age < age:
 
        print("too small...try again please")
 
    else:
 
        print("You guessed it !")
 
    if i%3 == 0:
 
        choice = input("Would you like play again? yes or no")
 
        if choice == "yes":
 
            continue
 
        if choice == "no":
 
            break
 
    else:
 
        continue

#登录验证,输入错误三次锁定用户

f = open('c:/user_passwd.txt','r')
 
j = 3
 
system_user_name = str(f.readline())
 
system_passwd = str(f.readline())
 
f.close()
 
for i in range(1,5):
 
    user_name = str(input("Please input your UserID:"))
 
    password = str(input("passwd:"))
 
    if i == 3:
 
        s = open('c:/user_passwd.txt', 'r+')
 
        s.write("\nlocked")
 
        s.close()
 
        print("This user is locked!")
 
        break
 
    else:
 
        if user_name + '\n' == system_user_name and password == system_passwd:
 
            print("Welcome" + user_name + '\n' + "Have a good time!")
 
            break
 
        else:
 
            j -= 1
 
            i += 1
            print("UserID or password is wrong,Please try once again and you have " + \              str(j) + 'times choice')

以上就是Python学习之函数及流程控制的详细内容,更多请关注其它相关文章!

相关标签: Python