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php将金额数字转化为中文大写_php技巧

程序员文章站 2022-05-03 16:00:58
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php将金额数字转化为中文大写
echo toChineseNumber(1234567890);//壹拾贰亿叁仟肆佰伍拾陆万柒仟捌佰玖拾圆
function toChineseNumber($money){
  $money = round($money,2);
  $cnynums = array("零","壹","贰","叁","肆","伍","陆","柒","捌","玖"); 
  $cnyunits = array("圆","角","分");
  $cnygrees = array("拾","佰","仟","万","拾","佰","仟","亿"); 
  list($int,$dec) = explode(".",$money,2);
  $dec = array_filter(array($dec[1],$dec[0])); 
  $ret = array_merge($dec,array(implode("",cnyMapUnit(str_split($int),$cnygrees)),"")); 
  $ret = implode("",array_reverse(cnyMapUnit($ret,$cnyunits))); 
  return str_replace(array_keys($cnynums),$cnynums,$ret); 
}
function cnyMapUnit($list,$units) { 
  $ul=count($units); 
  $xs=array(); 
  foreach (array_reverse($list) as $x) { 
    $l=count($xs); 
    if ($x!="0" || !($l%4)) 
      $n=($x=='0'?'':$x).($units[($l-1)%$ul]); 
    else $n=is_numeric($xs[0][0])?$x:''; 
 array_unshift($xs,$n); 
 } 
 return $xs; 
 }

代码二:

/**
*数字金额转换成中文大写金额的函数
*String Int $num 要转换的小写数字或小写字符串
*return 大写字母
*小数位为两位
**/
function num_to_rmb($num){
    $c1 = "零壹贰叁肆伍陆柒捌玖";
    $c2 = "分角元拾佰仟万拾佰仟亿";
    //精确到分后面就不要了,所以只留两个小数位
    $num = round($num, 2); 
    //将数字转化为整数
    $num = $num * 100;
    if (strlen($num) > 10) {
        return "金额太大,请检查";
    } 
    $i = 0;
    $c = "";
    while (1) {
        if ($i == 0) {
            //获取最后一位数字
            $n = substr($num, strlen($num)-1, 1);
        } else {
            $n = $num % 10;
        }
        //每次将最后一位数字转化为中文
        $p1 = substr($c1, 3 * $n, 3);
        $p2 = substr($c2, 3 * $i, 3);
        if ($n != '0' || ($n == '0' && ($p2 == '亿' || $p2 == '万' || $p2 == '元'))) {
            $c = $p1 . $p2 . $c;
        } else {
            $c = $p1 . $c;
        }
        $i = $i + 1;
        //去掉数字最后一位了
        $num = $num / 10;
        $num = (int)$num;
        //结束循环
        if ($num == 0) {
            break;
        } 
    }
    $j = 0;
    $slen = strlen($c);
    while ($j 

代码三:

 $max_len) {
return 'outnumber';
}
$num = str_pad($num,12,'-',STR_PAD_LEFT);
$exp_num = array();
$k = 0;
for($i=12;$i>0;$i--){
if($i%4 == 0) {
$k++;
}
$exp_num[$k][] = substr($num,$i-1,1);
}
$str = '';
foreach($exp_num as $key=>$nums) {
if(array_sum($nums)){
$str = array_shift($exp_cn) . $str;
}
foreach($nums as $nk=>$nv) {
if($nv == '-'){continue;}
if($nk == 0) {
$str = $convert_cn[$nv] . $str;
} else {
$str = $convert_cn[$nv].$unit_cn[$nk-1] . $str;
}
}
}
$str = str_replace($repair_number,array('万','亿','-'),$str);
$str = preg_replace("/-{2,}/","",$str);
$str = str_replace(array('零','-'),array('','零'),$str);
return $str;
}
echo convert_2_cn(1111)."\n";
echo convert_2_cn(111111)."\n";
echo convert_2_cn(111111111111)."\n";

//补充一个中文转数字的
function cn_2_num($str){
$convert_cn = array("零","壹","贰","叁","肆","伍","陆","柒","捌","玖");
$skip_words = array("拾","佰","仟");
$str = str_replace($skip_words,"",$str);
$len = mb_strlen($str,'utf-8');
$num = 0;
$k = '';
for($i=0;$i

代码四:

function convertCurrency(currencyDigits) {
// Constants:
var MAXIMUM_NUMBER = 99999999999.99;
// Predefine the radix characters and currency symbols for output:
var CN_ZERO = "零";
var CN_ONE = "壹";
var CN_TWO = "贰";
var CN_THREE = "叁";
var CN_FOUR = "肆";
var CN_FIVE = "伍";
var CN_SIX = "陆";
var CN_SEVEN = "柒";
var CN_EIGHT = "捌";
var CN_NINE = "玖";
var CN_TEN = "拾";
var CN_HUNDRED = "佰";
var CN_THOUSAND = "仟";
var CN_TEN_THOUSAND = "万";
var CN_HUNDRED_MILLION = "亿";
var CN_SYMBOL = "人民币";
var CN_DOLLAR = "元";
var CN_TEN_CENT = "角";
var CN_CENT = "分";
var CN_INTEGER = "整";
// Variables:
var integral; // Represent integral part of digit number. 
var decimal; // Represent decimal part of digit number.
var outputCharacters; // The output result.
var parts;
var digits, radices, bigRadices, decimals;
var zeroCount;
var i, p, d;
var quotient, modulus;
// Validate input string:
currencyDigits = currencyDigits.toString();
if (currencyDigits == "") {
 alert("Empty input!");
 return "";
}
if (currencyDigits.match(/[^,.\d]/) != null) {
 alert("Invalid characters in the input string!");
 return "";
}
if ((currencyDigits).match(/^((\d{1,3}(,\d{3})*(.((\d{3},)*\d{1,3}))?)|(\d+(.\d+)?))$/) == null) {
 alert("Illegal format of digit number!");
 return "";
}
// Normalize the format of input digits:
currencyDigits = currencyDigits.replace(/,/g, ""); // Remove comma delimiters.
currencyDigits = currencyDigits.replace(/^0+/, ""); // Trim zeros at the beginning. 
// Assert the number is not greater than the maximum number.
if (Number(currencyDigits) > MAXIMUM_NUMBER) {
 alert("Too large a number to convert!");
 return "";
}
// http://www.knowsky.com/ Process the coversion from currency digits to characters:
// Separate integral and decimal parts before processing coversion:
parts = currencyDigits.split(".");
if (parts.length > 1) {
 integral = parts[0];
 decimal = parts[1];
 // Cut down redundant decimal digits that are after the second.
 decimal = decimal.substr(0, 2);
}
else {
 integral = parts[0];
 decimal = "";
}
// Prepare the characters corresponding to the digits:
digits = new Array(CN_ZERO, CN_ONE, CN_TWO, CN_THREE, CN_FOUR, CN_FIVE, CN_SIX, CN_SEVEN, CN_EIGHT,CN_NINE);
radices = new Array("", CN_TEN, CN_HUNDRED, CN_THOUSAND);
bigRadices = new Array("", CN_TEN_THOUSAND, CN_HUNDRED_MILLION);
decimals = new Array(CN_TEN_CENT, CN_CENT);
// Start processing:
outputCharacters = "";
// Process integral part if it is larger than 0:
if (Number(integral) > 0) {
 zeroCount = 0;
 for (i = 0; i  0)
  {
   outputCharacters += digits[0];
  }
  zeroCount = 0;
  outputCharacters += digits[Number(d)] + radices[modulus];
  }
  if (modulus == 0 && zeroCount 转换成一个0
  //以下确定输入的为过滤后的合法数字
  //alert(ms);
  var txt = ms.split(".");
  //alert(txt[0]);
  //如果ms值不小数点存在则txt[0]=小数点前的值否则等于ms
  //regexp:/\d{4}(,|$)/ 匹配四位数字和,的集合或者四位数字和字符结尾的集合
  while(/\d{4}(,|$)/.test(txt[0]))//如果为txt[0]=4123
   txt[0] = txt[0].replace(/(\d)(\d{3}(,|$))/,"$1,$2");
  //txt[0].replace(/(\d)(\d{3}(,|$))/,"$1,$2")是将txt[0]进行替换后再赋给它
  //regexp:/(\d)(\d{3}(,|$))/ 将四个数字份为两组第一个数字为第一位,后三位和其他结尾为每二位
  //并替换成 第一位,第二位 注意 ,的使用很好.  也就是将4123先替换成4,123
  //由于此表达式默认采用贪婪匹配所以从数值后向前匹配再通过循环进行再匹配替换从而可以将
  //12345678分成你想要的123,456,78 彩用(,|$)很精典,因为它略去了第二次匹配时的,问题
  t.value = stmp = txt[0]+(txt.length>1?"."+txt[1]:"");
  //最终赋值到输入框中 
  //如果有小数点则加上并购成最终数字否则显示替换后的txt[0]
  bbb.value = convertCurrency(ms-0);
  //将ms转换为数字送到number2num1去转换
}

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