python爬虫2：利用Requests和 XPATH爬取猫眼电影TOP100榜单

import requests
from lxml import etree
def get_one_page(url):#得到1页的数据
  headers = {
    'User-Agent':'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/64.0.3282.140 Safari/537.36'
    }
  response=requests.get(url)
  if response.status_code == 200:  # 页面正常响应
      return response.text  # 返回页面源代码
  return None
def save_data():
     for i in range(0,10):#多页爬取
         url = 'https://maoyan.com/board/4?offset='+str(i*10)
         html = get_one_page(url)
         s = etree.HTML(html)
         titles = s.xpath('//*[@id="app"]/div/div/div/dl/dd/div/div/div[1]/p[1]/a/text()')#返回的是一个列表
         for title in titles:#把数据每一条提取出来并保存数据
            print(title)
            with open('manyan1.txt','a',encoding='utf8') as f:#保存爬取的数据到txt文档
                f.write(title+'\n')
if __name__ =='__main__':
     save_data()#开始爬虫

1.本文利用Requests与XPATH爬取猫眼电影TOP100的榜单

2.由于本人初学爬虫有什么不对的地方请指正