把字符串按照特定的字母顺序进行排序的js代码_javascript技巧
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2022-05-01 12:23:28
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例如,给一个特定的字母顺序,"a","o","e","u","y","i",请把'aiye','oeu','ayo','eoyiu','yuo','you','iao'这7个字符串按照给定的字母顺序排序。
我的思路是把那几个给定的6个字母分别等效成0-5的数字,然后把那7个字符串中的字母替换成0-5中的数字,再用sort方法进行排序,代码如下:
var word = ['aiye','oeu','ayo','eoyiu','yuo','you','iao'];
var obj = {a:0,o:1,e:2,u:3,y:4,i:5};
var obj1 = {0:'a',1:'o',2:'e',3:'u',4:'y',5:'i'};
for(var index in word){
var word1 = word[index];
var word3 = "";
for(var i = 0; iword3 += obj[word1[i]];
};
word[index] = word3
}
word.sort();
for(var index in word){
var word1 = word[index];
var word3 = "";
for(var i = 0; iword3 += obj1[word1[i]];
};
word[index] = word3
}
console.log(word);
我的思路是把那几个给定的6个字母分别等效成0-5的数字,然后把那7个字符串中的字母替换成0-5中的数字,再用sort方法进行排序,代码如下:
复制代码 代码如下:
var word = ['aiye','oeu','ayo','eoyiu','yuo','you','iao'];
var obj = {a:0,o:1,e:2,u:3,y:4,i:5};
var obj1 = {0:'a',1:'o',2:'e',3:'u',4:'y',5:'i'};
for(var index in word){
var word1 = word[index];
var word3 = "";
for(var i = 0; iword3 += obj[word1[i]];
};
word[index] = word3
}
word.sort();
for(var index in word){
var word1 = word[index];
var word3 = "";
for(var i = 0; iword3 += obj1[word1[i]];
};
word[index] = word3
}
console.log(word);
复制代码 代码如下:
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