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php采用curl模仿登录人人网发布动态的方法,curl人人

程序员文章站 2022-04-30 18:16:25
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php采用curl模仿登录人人网发布动态的方法,curl人人

本文实例讲述了php采用curl模仿登录人人网发布动态的方法。分享给大家供大家参考。具体实现方法如下:

说到php中模仿登录很多人第一时间会想到curl函数系列了,这个没错本例子也是使用curl模仿登录之后再进行动态发布,原理也简单我们只要抓取人人网的登录信息,然后再由curl post登录数据上去就可以了。

具体代码如下:

复制代码 代码如下:

$rconfig = pdo_fetch("SELECT * FROM ".tablename("eduTwo_renren")." WHERE weid = :weid",array(':weid'=>$_W['weid']));

$cookie_file = dirname(__FILE__)."/renren.cookie";
$login_url = 'http://passport.renren.com/PLogin.do';
$post_fields['email'] = $rconfig['rusername'];
$post_fields['password'] = $rconfig['rpassword'];
$post_fields['origURL'] = 'http%3A%2F%2Fhome.renren.com%2FHome.do';
$post_fields['domain'] = 'renren.com';

$ch = curl_init($login_url);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; zh-CN; rv:1.9.1.5) Gecko/20091102 Firefox/3.5.5');
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_MAXREDIRS, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_AUTOREFERER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post_fields);
curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie_file);
$content = curl_exec($ch);
$info = curl_getinfo($ch);
curl_close($ch);
//var_dump($info);exit;
//匹配用户的ID
$send_url='http://www.renren.com/home';
$ch = curl_init($send_url);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file);
curl_exec($ch);
$info = curl_getinfo($ch);
curl_close($ch);

//$uid = "305115027";
//获取token和rtk
$send_url=$info['redirect_url'];
$ch = curl_init($send_url);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file);
$tmp = curl_exec($ch);
curl_close($ch);
preg_match_all("/get_check:'(.*?)',get_check_x:'(.*?)',/is",$tmp,$arr);
preg_match_all("/'ruid':'(.*?)',/is",$tmp,$utmp);
//var_dump($utmp);exit;
$token = $arr[1][0];//1121558104
$rtk = $arr[2][0];//e9a9cb2
$uid = $utmp[1][0];
//echo $token;exit;
//发布信息
$poststr['content'] = $_GPC['content'].$rconfig['tail'];
$poststr['withInfo'] = '{"wpath":[]}';
$poststr['hostid:'] = $uid;
$poststr['privacyParams'] = '{"sourceControl": 99}';
$poststr['requestToken'] = $token;
$poststr['_rtk'] = $rtk;
$poststr['channel'] = "renren";
$head = array(
'Referer:http://shell.renren.com/ajaxproxy.htm',
'X-Requested-With:XMLHttpRequest',
);
$ch = curl_init("http://shell.renren.com/{$uid}/status");
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; Windows NT 5.1; zh-CN; rv:1.9.1.5) Gecko/20091102 Firefox/3.5.5');
curl_setopt($ch,CURLOPT_HTTPHEADER,$head);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_MAXREDIRS, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_AUTOREFERER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $poststr);
curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file);
$content = curl_exec($ch);
curl_close($ch);
//echo $content;exit;
$data = json_decode($content,true);
if($data["code"] == "0"){
echo "发布成功!";
}else{
echo "shit !!!";
}

最后就发布成功了,当然前面的数据库需要自己写一个吧,非常的简单的一个记录库也是你要发布的信息。录数据上去就可以了。

希望本文所述对大家的PHP程序设计有所帮助。

PHP CURL POST模拟用户登录了希望可以给出具体的代码,并简要解释下代码

你可以看下是否有其它的http header没有模拟,比如Referer和User-Agent是否都能模拟浏览器的值,一个完整的请求是类似于这样的:
GET /home/pack/data/content?id=31,2399,13,30&asyn=1&t=0.03439752989200834&_req_seqid=0xa982225f0637c78a HTTP/1.1
Accept: */*
Accept-Language: zh-cn
Referer: www.baidu.com/
x-requested-with: XMLHttpRequest
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; BTRS123401; InfoPath.2; .NET CLR 2.0.50727; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729; .NET4.0C; MS-RTC LM 8)
Host: www.baidu.com
Connection: Keep-Alive
Cookie: XCXXXXX
 

我按照php100的代码做,为何这个php cURL还是不可以实现模拟登陆

$post_fields = 'cktime=31536000&step=2&pwuser=账号&pwpwd=密码';账号密码改成你自己的试试,我试过是可以的

 

相关标签: php curl curl