代码示例展现PHP二级联动菜单的实现_PHP教程
程序员文章站
2022-04-29 18:14:31
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对于初学者来说,
PHP二级联动菜单代码示例:
- script language = "JavaScript">
- var onecount;
- onecount=0;
- subcat = new Array();
- ?php
- mysql_connect("localhost","charles",
"charles"); - mysql_select_db( "_crm" );
- $sql = "select * from site";
- $result = mysql_query( $sql );
- $count = 0;
- while($res = mysql_fetch_row($result)){
- ?>
-
subcat[ ?php echo $count ?>] = new Array
(" ?php echo $res[0]?>"," ?php echo
$res[2]?>"," ?php echo $res[1]?>"); - ?php
- $count++;
- }
- echo "onecount=$count;";
- ?>
- //联动函数
- function changelocation(locationid)
- {
- document.myform.ctype.length = 0;
- var locationidlocationid=locationid;
- var i;
- for (i=0;i onecount; i++)
- {
- if (subcat[i][2] == locationid)
- {
-
//var newnewOption1=new Option(subcat[i]
[1], subcat[i][0]); - //document.all.ctype.add(newOption1);
- document.myform.ctype.options[document.
myform.ctype.length] = new Option(subcat
[i][1], subcat[i][0]); - }
- }
- }
- /script>
-
form method="post" name="myform"
action="ru_query.php"> -
select name="type" onChange="changelocation(
document.myform.type.options[document.myfo
rm.type.selectedIndex].value)" size="1"> - option selected value="">main /option>
- ?php
- $sql = "select * from entreprise";
- $result = mysql_query( $sql );
- while($res = mysql_fetch_row($result)){
- ?>
- option value="">
- ?php echo $res[1]; ?> /option>
- ?php } ?>
- /select>
- select name="ctype">
- option selected value="">sub /option>
- /select>
- input type="submit" name="Submit" value="search">
- /form>
以上代码就是PHP二级联动菜单的具体实现方法。
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