ajax+php实现无刷新验证手机号的实例
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2022-04-29 12:16:43
一款简单的无刷新验证手机号是否注册:
客户端实现:
&...
一款简单的无刷新验证手机号是否注册:
客户端实现:
<!doctype html> <html> <head> <meta charset="utf-8"> <style> #btn{width:80px;height:30px;} </style> </head> <body> <form> 请输入手机号: <input type="text" id="name" name="name"> <input type="button" onclick="show()" id="btn" value="验证"> </form> <p id="txt"></p> <script> var usernamereg = /^1(3|4|5|7|8)\d{9}$/; function show(){ var name=document.getelementbyid("name").value; var xmlhttp=new xmlhttprequest(); var url="post.php"; xmlhttp.onreadystatechange=function statechanged() { if (xmlhttp.readystate==4 || xmlhttp.readystate=="complete"){ if(!usernamereg.test(name)){ document.getelementbyid("txt").innerhtml="手机号有误"; }else{ document.getelementbyid("txt").innerhtml=xmlhttp.responsetext } } } xmlhttp.open("post",url,true); xmlhttp.setrequestheader("content-type","application/x-www-form-urlencoded"); xmlhttp.send("name=" + name); } </script> </body> </html>
服务端实现:
<?php $con = mysqli_connect('localhost', 'username', 'password'); if(! $con ) { die('连接失败: ' . mysqli_error($con)); } mysqli_select_db($con,'bdm256727651_db'); $username = "select username from forms where username = '$_post[name]' "; $result = mysqli_query($con,$username ); $rows=mysqli_num_rows($result); if($rows){ echo "手机号已注册" ; exit; }else{ echo "手机号可用"; } mysqli_close($con) ?>
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