Jquery+ajax+springMVC如何返回json
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2022-04-28 08:43:01
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JSP页面：
<%@ page language="java" contentType="text/html; charset=utf-8" pageEncoding="utf-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>登录验证</title>
<script type="text/javascript" src="js/jquery-1.8.3.js"></script>
<script type="text/javascript">
$(function(){
//ajax验证
$("#ajax1").click(function(){
alert(1);
$.post(
"ajax1.action",
function(result){
alert(2);
alert(result.ms);
}
);
});
});
</script>
</head>
<body>
<p id="con">
<p class="center"><h2>欢迎登录</h2></p>
<p>
<form action="login.action" method="post">
<table>
<tr>
<td>用户名：</td>
<td colspan="3"><input type="text" name="name"/></td>
<td></td>
</tr>
<tr>
<td>密 码：</td>
<td colspan="3"><input type="password" name="pwd"/></td>
<td></td>
</tr>
<tr>
<td>用户名：</td>
<td><input type="text" name="code"/></td>
<td></td>
</tr>
<tr>
<td class="center">
<input type="submit" name="sub" value="登录"/>
</td>
</tr>
<tr>
<td>
<button id="ajax1">ajax测试1</button>
</td>
</tr>
</table>
</form>
</p>
</p>
</body>
</html>
后台控制类：
package com.login.control;
import javax.servlet.http.HttpServletRequest;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.servlet.ModelAndView;
import com.alibaba.fastjson.JSONObject;
import com.login.bean.Users;
import com.login.service.UsersService;
/**
* 用户控制类
* @author
*
*/
@Controller
public class UsersControl {
@RequestMapping(value="ajax1.action",method= RequestMethod.POST) @ResponseBody
public Object ajax1(HttpServletRequest request){
System.out.println("进入控制类");
JSONObject json = new JSONObject();
String ms = "ajax测试1成功！哈哈!";
json.put("ms", ms);
System.out.println("出控制类");
return json;
}
}
必须加这两句才能返回json值
@RequestMapping(value="ajax1.action",method= RequestMethod.POST) @ResponseBody
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