shell脚本操作mysql数据库删除重复的数据

由于之前的业务，造成数据库上产生了脏数据，写个脚本删除重复的数据。由于是开发测试环境，所以选择任意删除相同uid中的一条。由于每次执行只删除重复数据的一条，需要重复执行，如果本轮没有数据被删就ok

#!/bin/sh
# delete all company's duplicate uid
mysql_bin_path=/data/mysql/server/mysql_3306/bin
mysql_sock_path=/data/mysql/server/mysql_3306/tmp
dbuser=dbuser
dbpwd=userpwd
dbhostname=192.168.1.105
port=3306
# get all company_id
for company_id in `${mysql_bin_path}/mysql -u${dbuser} -p${dbpwd} -h ${dbhostname} -p ${port} --socket=${mysql_sock_path}/mysql.sock -e "
  select company_id from company.companypage;"`
do
 if [ $company_id != "company_id" ] ; then
# if [ $company_id -eq 2733 ] ; then 
 suffix=`expr ${company_id} % 100`
 for user_id in `${mysql_bin_path}/mysql -u${dbuser} -p${dbpwd} -h ${dbhostname} -p ${port} --socket=${mysql_sock_path}/mysql.sock -e "
 select user_id from company.company_candidate_${suffix} where company_id=${company_id} and user_id>0 group by company_id, user_id having count(user_id) > 1;"`
 do
 if [ $user_id != "user_id" ] ; then
  ${mysql_bin_path}/mysql -u${dbuser} -p${dbpwd} -h ${dbhostname} -p ${port} --socket=${mysql_sock_path}/mysql.sock -e "
  delete from company.company_candidate_${suffix} where company_id=${company_id} and user_id=${user_id} limit 1;" 
  echo "delete from company_candidate_${suffix} where company_id=${company_id} and user_id=${user_id} limit 1"
 fi
 done
# fi
 fi
done
exit 0

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