php采集一网站的精美图片
程序员文章站
2022-04-27 08:14:06
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php代码
<?php header("Content-type:text/html;charset=utf-8"); function GrabImage($url,$filename="") { if($url==""):return false;endif; if($filename=="") { $ext=strrchr($url,"."); if($ext!=".gif" && $ext!=".jpg"):return false;endif; $filename=date("dMYHis").$ext; } ob_start(); readfile($url); $img = ob_get_contents(); ob_end_clean(); $size = strlen($img); $fp2=@fopen($filename, "w+"); fwrite($fp2,$img); fclose($fp2); return $filename; } for($i=1;$i<8;$i++){ $url="http://www.topit.me/popular/20120420?p=".$i; echo $url; $file=file_get_contents($url); $preg='/(.*)<div class="e">(.*)<\/div>(.*)/isU'; preg_match_all($preg,$file,$string); set_time_limit(0); foreach($string[2] as $key=>$value){ //echo $value; $pattern_src = '/href="(.*)"><img class="img" title="(.*)"/isU'; preg_match_all($pattern_src,$value,$str); print_r($str."<br/>"); $img=GrabImage($str[1][0],"",""); if($img){ echo 'sucess'; }else{ echo "false"; } } } ?>
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