C语言题目---奇偶个数，数字特征值，素数和，念整数

#include <stdio.h>

int main()
{
int n;
scanf("%d",&n);
int i=0;int j=0;

while(n<100000,n != -1){\\条件
if(n%2 != 0){\\奇偶判断
i++;
}else{
j++;
}
scanf("%d",&n);
if(n == -1){break;}\\输入结束
}
printf("%d %d", i, j);

return 0;
}

#include <stdio.h>

int main() {
int n, i;
int q = 0;
scanf("%d", &n);
int t = n;
int count = 0;

while(t != 0) {
i = t%10; //数字
t /= 10;
count++; //数位
int m = 1;
int A = i%2; int B = count%2;
if((A != 0 && B != 0) || (A == 0 && B == 0)) {
for(int c = 1; c < count; c++) {
m *= 2;
}//二进制值
}else{
m = 0;
}//奇偶判断
q = q+m;
}

printf("%d", q);

return 0;
}

#include <stdio.h>
int main()
{
int n, m, i, j;
int flag=1, cnt=0, sum=0;

scanf("%d %d",&n, &m);
if(n>0 && n<=m && m<=200){\\条件
for(i=2; cnt<m; i++){\\素数判断
flag=1;
for(j=2; j<i; j++){
if(i%j == 0){
flag = 0;
break;
}
}
if(flag == 1 ){\\计数
cnt++;
if(cnt>=n && cnt<=m){
sum += i;
}
}
}
}
printf("%d",sum);

return 0;
}

#include <stdio.h>
int main()
{
int n, m, k, t, i;
scanf("%d",&n);

if(n >= -100000 && n <= 100000){\\条件
if(n<0){\\负数
printf("%s ","fu");
n = n*(-1);
}
m=n; k=1;
while(m>9){\\数位
m /= 10;
k *= 10;
}
for(t=n; k>0; k/=10){\\数字
i = t/k;
t = t%k;
switch ( i ){\\拼音
case 0:
printf("ling");
break;
case 1:
printf("yi");
break;
case 2:
printf("er");
break;
case 3:
printf("san");
break;
case 4:
printf("si");
break;
case 5:
printf("wu");
break;
case 6:
printf("liu");
break;
case 7:
printf("qi");
break;
case 8:
printf("ba");
break;
case 9:
printf("jiu");
break;
}
if(k>9){printf(" ");}\\空格
}
}

return 0;
}