三种随便密码生成sql存储过程

本文章分享了几款关于三种随便密码生成sql存储过程，有需要学习的同学可以参考一下下哈。

随机产生密码，Insus.NET总结了三个，并分别写成了存储过程。

第一个，

代码如下

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usp_RandomPassword CREATE PROCEDURE [dbo].[usp_RandomPassword] ( @Length INT = 8 ) AS BEGIN DECLARE @RandomPassword NVARCHAR(MAX) = N'',@L INT = 1 WHILE @L BEGIN --随机产生每一位字符，ASCII码48至122 DECLARE @RndChar CHAR(1) = CHAR(ROUND(RAND() * (122-48+1) + 48,0)) --随机产生的字符不包括下面字符 IF ASCII(@RndChar) NOT IN(58,59,60,61,62,63,64,91,92,93,94,95,96) -- : , ; , , ? ,@ , [ , , ] , ^ , _ , ` BEGIN SET @RandomPassword = @RandomPassword + @RndChar SET @L = @L + 1 END END SELECT @RandomPassword END

第二个，

代码如下

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usp_RandomPassword CREATE PROCEDURE [dbo].[usp_RandomPassword] ( @Length INT = 8 ) AS BEGIN DECLARE @RandomPassword NVARCHAR(MAX) = N'',@L INT = 1 --随机密码将由下面字符串产生，数字0-9,大写字母A-Z,小写字母a-z DECLARE @BaseString VARCHAR(255) = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz' WHILE @L BEGIN --61是变量@BaseString的长度减一 SET @RandomPassword = @RandomPassword + SUBSTRING(@BaseString, CONVERT(INT,ROUND(RAND() * 61 + 1,0)),1) SET @L = @L + 1 END SELECT @RandomPassword END

第三个，

代码如下

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usp_RandomPassword CREATE PROCEDURE [dbo].[usp_RandomPassword] ( @Length INT = 8 ) AS BEGIN DECLARE @RandomPassword NVARCHAR(MAX) = N'' DECLARE @R TINYINT,@L INT = 1 WHILE @L BEGIN SET @R = ROUND(RAND() * 2, 0) --随机产生0,1,2整数 IF @R = 0 --当变量为0时，将随机产生一位数字 SET @RandomPassword = @RandomPassword + CHAR(ROUND(RAND() * 9 + 48,0)) ELSE IF @R = 1 --当变量为1时，将随机产生一位大写字母 SET @RandomPassword = @RandomPassword + CHAR(ROUND(RAND() * 25 + 65,0)) ELSE IF @R = 2 --当变量为2时，将随机产生一位小写字母 SET @RandomPassword = @RandomPassword + CHAR(ROUND(RAND() * 25 + 97,0)) SET @L = @L + 1 END SELECT @RandomPassword END

最后一个也可以重构写成：

代码如下

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usp_RandomPassword CREATE PROCEDURE [dbo].[usp_RandomPassword] ( @Length INT = 8 ) AS BEGIN DECLARE @RandomPassword NVARCHAR(MAX) = N'',@L INT = 1 WHILE @L BEGIN DECLARE @R INT = ROUND(RAND() * 2, 0) SET @RandomPassword = @RandomPassword + CASE @R WHEN 0 THEN CHAR(ROUND(RAND() * 9 + 48,0)) WHEN 1 THEN CHAR(ROUND(RAND() * 25 + 65,0)) WHEN 2 THEN CHAR(ROUND(RAND() * 25 + 97,0)) END SET @L = @L + 1 END SELECT @RandomPassword END Also reference: