欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  数据库

从MySQL的源码剖析Innodb buffer的命中率计算_MySQL

程序员文章站 2022-04-18 23:20:28
...
按官方手册推荐Innodb buffer Hit Ratios的计算是:

100-((iReads / iReadRequests)*100)
iReads : mysql->status->Innodb_buffer_pool_reads
iReadRequests: mysql->status->Innodb_buffer_pool_read_requests

出处: http://dev.mysql.com/doc/mysql-monitor/2.0/en/mem_graphref.html
搜”Hit Ratios”
推荐有兴趣的同学把这个页面都看一下应该也会有很大收获.
另外在hackmysql: www.hackmysql.com网站上的: mysqlsqlreport中关于buffer命中计算是:


$ib_bp_read_ratio = sprintf "%.2f",
($stats{'Innodb_buffer_pool_read_requests'} ?
100 - ($stats{'Innodb_buffer_pool_reads'} /
$stats{'Innodb_buffer_pool_read_requests'}) * 100 :0);

即:

ib_bp_hit=100-(Innodb_buffer_pool_reads/Innodb_buffer_pool_read_requests)*100

另外我们知道查看Innodb Buffer Hit Ratios的地方是:

代码如下:

show engine innodb status\G;


Buffer pool hit rate : XXXX/1000;
那个XXX/1000即是buffer pool hit ratios的命中.
这样也可以从代码里看一下这个bp命中计算:

storage/innobase/buf/buf0buf.c # void buf_print_io
storage/innodbase/include/buf0buf.h #struct buf_block_struct

在buf0buf.c 中的buf_print_io函数中可以看到:

void
buf_print_io(
…
 
if (buf_pool->n_page_gets > buf_pool->n_page_gets_old) {
fprintf(file, "Buffer pool hit rate %lu / 1000\n",
(ulong)
(1000 - ((1000 * (buf_pool->n_pages_read
- buf_pool->n_pages_read_old))
/ (buf_pool->n_page_gets
- buf_pool->n_page_gets_old))));
} else {
fputs("No buffer pool page gets since the last printout\n",
file);
}
 
buf_pool->n_page_gets_old = buf_pool->n_page_gets;
buf_pool->n_pages_read_old = buf_pool->n_pages_read;
…
}

结合:
storage\innobase\include\buf0buf.h中

struct buf_block_struct{
…
ulint n_pages_read; /* number read operations */
…
ulint n_page_gets; /* number of page gets performed;
also successful searches through
the adaptive hash index are
counted as page gets; this field
is NOT protected by the buffer
pool mutex */
…
ulint n_page_gets_old;/* n_page_gets when buf_print was
last time called: used to calculate
hit rate */
…
ulint n_pages_read_old;/* n_pages_read when buf_print was
last time called */
…


从这个来看innodb buffer hit Ratios的命中计算需要本次取的值和上次值做一个减法公式应该为

ib_bp_hit=1000 – (t2.iReads – t1.iReads)/(t2.iReadRequest – t1.iReadRequest)*1000

t(n): 时间点 两个时间间隔最少是30秒以上,在小意义不大.

iReads: Innodb_buffer_pool_reads
iReadRequest: Innodb_buffer_pool_read_requests

对innodb的输出参数有兴趣的可以关注: storage/innobase/buf/Srv0srv.c 中的:

void srv_export_innodb_status()

思考:
对于innodb_buffer_pool_read_requests, innodb_buffer_pool_reads这种累加值,当很大时进行: innodb_buffer_pool_reads/innodb_buffer_pool_read_requests 相来讲只能得到从开始到现在的命中率的表现了. 如果想得到现在近五分钟,近一分钟或是8点到9点每分钟的命中率情况,如果还是按着innodb_buffer_pool_reads/innodb_buffer_pool_read_requests 进行计算,只能得到mysqld开起累计在8点-9点的每分钟的累计平均命中情况.
所以如果想到每(五)分钟的命中情况,就需要本次取得的值和一(五)分钟前的值进行相减,然后进行运算.这样才能得到一个当下的bp命中情况.
两种方法没实质的对错的问题,但相对于源码中的那种计算方式更容让发现数据库的抖动问题.

能解决的问题:
偶而的数据库性能抖动能直观的反应出来.

相关标签: MySQL