Go遍历struct,map,slice的实现
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2022-04-18 17:17:33
遍历结构体如何实现遍历结构体字段? 好吧,言归正传!举个例子:demo1:package mainimport ( "fmt" "reflect")type student struc...
遍历结构体
如何实现遍历结构体字段? 好吧,言归正传!举个例子:
demo1:
package main import ( "fmt" "reflect" ) type student struct { name string age int } func main() { v := reflect.valueof(student{"乔峰", 29}) count := v.numfield() for i := 0; i < count; i++ { f := v.field(i) //字段值 switch f.kind() { case reflect.string: fmt.println(f.string()) case reflect.int: fmt.println(f.int()) } } }
再举给栗子:
package main import ( "fmt" "reflect" ) type lantype struct { s1, s2, s3 string } var language interface{} = lantype{"php", "go", "python3"} func main() { value := reflect.valueof(language) for i := 0; i < value.numfield(); i++ { fmt.printf("字段索引 %d: %v\n", i, value.field(i)) } }
输出:
basic
字段索引 0: php
字段索引 1: go
字段索引 2: python3
遍历切片
使用 for range遍历:
package main import ( "fmt" ) func main() { language := []string{"php", "go", "python3"} for k, val := range language { fmt.printf("切片索引 %d is :%s\n", k, val) } }
输出:
basic
切片索引 0 is :php
切片索引 1 is :go
切片索引 2 is :python3
遍历map
package main import ( "fmt" ) func main() { language := make(map[string]string) language["1"] = "php" language["2"] = "go" language["3"] = "python3" language["4"] = "c#" for key, val := range language { fmt.printf("%v=>%v\n", key, val) } }
输出:这里就不贴了,结果会随机输出,因为map遍历出来结果是无序的,顺序不好控制,也不利于业务逻辑;当业务依赖key次序时,那么我们就需要引入“sort”包来解决随机化问题:
比如这样:
package main import ( "fmt" "sort" ) func main() { language := make(map[string]string) language["1"] = "php" language["2"] = "go" language["3"] = "python3" language["4"] = "c#" sorted_keys := make([]string, 0) for k, _ := range language { sorted_keys = append(sorted_keys, k) // 提取键名 } sort.strings(sorted_keys) // for _, k := range sorted_keys { fmt.printf("%v=>%v\n", k, language[k]) } }
输出:
basic
1=>php
2=>go
3=>python3
4=>c#
这样输出的结果运行多次也不会改变顺序。
golang json序列化(struct,int,map,slice)
package main import ( "encoding/json" "fmt" ) //把结构体都改小写 type user struct { username string `json:"user_name"` //json的tag标记 nickname string `json:"nickname"` age int birthday string sex string email string phone string } func teststruct() { user1 := &user{ username: "超哥", nickname: "大头哥", age: 18, birthday: "2008/8/8", sex: "男", email: "mahuateng@qq.com", phone: "110", } //开始json序列化 data, err := json.marshal(user1) if err != nil { fmt.printf("json.marshal failed,err:", err) return } fmt.printf("%s\n", string(data)) } func testint() { var a = 18 //开始json序列化 data, err := json.marshal(a) if err != nil { fmt.printf("json.marshal failed,err:", err) return } fmt.printf("%s\n", string(data)) } func testmap() { var m map[string]interface{} //声明map m = make(map[string]interface{}) //必须初始化map分配内存 m["username"] = "user1" m["age"] = 18 m["sex"] = "man" fmt.println(m) data, err := json.marshal(m) if err != nil { fmt.printf("json.marshal failed,err:", err) return } fmt.printf("%s\n", string(data)) } func testslice() { //定义一个slice,元素是map var m map[string]interface{} var s []map[string]interface{} m = make(map[string]interface{}) m["username"] = "user1" m["age"] = 18 m["sex"] = "man" s = append(s, m) m = make(map[string]interface{}) m["username"]="user2" m["age"]=188 m["sex"]="male" s=append(s,m) data, err := json.marshal(s) if err != nil { fmt.printf("json.marshal failed,err:", err) return } fmt.printf("%s\n", string(data)) } func main() { teststruct() //结构体的序列化 testint()//序列化数值 testmap()//序列化map testslice()//序列化切片 }
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