将字符串中的标点符号过滤掉
程序员文章站
2022-04-17 22:13:56
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开发中我们有可能会遇到这种情况,就是将字符串中的某个字符去掉
PHP代码
@Test public void test() { String d = trimPunctuation2("你,好oewefo,21.2!;:、1?dsf"); System.out.println(d); } // 将字符串中的标点符号过滤掉 public static String trimPunctuation2(String str) { String punct[] = { ",", ".", "!", "?", ";", ":", ",", "。", "!", "?", ";", ":", "、" }; List<String> punctList = Arrays.asList(punct); // 将String数组转List集合 StringBuilder result = new StringBuilder(); for (int i = 0; i < str.length(); i++) { Character c = str.charAt(i); if (punctList.contains(c.toString())) { } else { result.append(str.charAt(i)); } } return result.toString(); } // 将字符串中的标点符号过滤掉 public static String trimPunctuation(String str) { StringBuilder result = new StringBuilder(); for (int i = 0; i < str.length(); ++i) { char punct[] = { ',', '.', '!', '?', ';', ':', ',', '。', '!', '?', ';', ':', '、' }; boolean need_filter = false; for (int j = 0; j < punct.length; ++j) { if (punct[j] == str.charAt(i)) { need_filter = true; break; } } if (!need_filter) { result.append(str.charAt(i)); } } return result.toString(); }