正则表达式的字符串替换方法

我有以下几行：

d:\projects\qqq\development\qqq.mysol1.sln
d:\projects\qqq\qqqdevelopment\qqqmysol2.sln
d:\projects\qqq\development\myinstaller.sln
d:\projects\qqq\qqq\development\myinstaller.sln
d:\projects\development\myinstaller.sln

我需要一个正则表达式，这将导致捕获：

line 1: development and mysol1.sln
line 2: development and mysol2.sln
line 3: development and myinstaller.sln
line 4: development and myinstaller.sln
line 5: development and myinstaller.sln

因此，一个正则表达式，将删除（忽略）字qqq从行。 我一直在试图与调节，并有部分的解决方案：

.*\\(?<a>.*)\\.{3}(?<b>.*)

这导致：

line 1: development and .mysol1.sln
line 2: qqqdevelopment and mysol2.sln
line 3: development and nstaller.sln
line 4: development and nstaller.sln
line 5: development and nstaller.sln

因此，.{3}应固定

1.我认为，应该工作：

.*\\(?:qqq)?(?<a>.*)\\(?:qqq)?(?<b>.*)