YII框架中搜索分页jQuery写法详解
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2022-04-10 17:06:51
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控制层
use frontend\models\StudUser; use yii\data\Pagination; use yii\db\Query; /** * 查询 * */ public function actionSearch() { //接值 $where=Yii::$app->request->get(); //实例化query $query=new Query(); $query->from('stud_user'); //判断 if(isset($where['sex'])&&$where['sex']!=''){ //判断 if($where['sex']=='男'){ $query->andWhere(['stud_sex'=>0]); } if($where['sex']=='女'){ $query->andWhere(['stud_sex'=>1]); } }else{ $where['sex']=''; } //年龄 if(isset($where['age'])&&$where['age']!=''){ $query->andWhere(['>','stud_age',$where['age']]); }else{ $where['age']=''; } //分页 $pagination = new Pagination(['totalCount' => $query->count()]); //条数 $pagination->setPageSize('3'); //条件 $query->offset($pagination->offset)->limit($pagination->limit); //执行 $userInfo=$query->all(); //print_r($userInfo);die; return $this->render('search',['userInfo'=>$userInfo,'page'=>$pagination,'where'=>$where]); }
模型层
<?php namespace frontend\models; use Yii; use yii\db\ActiveRecord; class StudUser extends ActiveRecord { /** * 声明表名 * */ public static function tableName() { return '{{%stud_user}}'; } /** * 验证规则 * */ public function rules() { return [ ['stud_age','integer'], ]; } }
视图层
<?php use yii\widgets\ActiveForm; use yii\helpers\Url; use yii\helpers\Html; use yii\widgets\LinkPager; ?> <?php $form=ActiveForm::begin([ 'action'=>Url::toRoute(['admin/search']), 'method'=>'get', ]); echo '性别'," ",Html::input('text','sex',$where['sex']); echo '年龄'," ",Html::input('text','age',$where['age']); echo Html::submitButton('提交'); ActiveForm::end(); ?> <table class="table"> <tr> <td>序号</td> <td>姓名</td> <td>年龄</td> </tr> <?php foreach($userInfo as $val):?> <tr> <td><?= $val['stud_id']?></td> <td><?= $val['stud_name']?></td> <td><?= $val['stud_age']?></td> </tr> <?php endforeach;?> </table> <?php echo LinkPager::widget([ 'pagination' => $page, 'nextPageLabel'=>'下一页' ]);?>
分页的样式在
LinkPager.php中
以上所述是小编给大家介绍的YII框架中搜索分页jQuery写法详解,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对PHP中文网的支持!
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