ajax实现远程通信
程序员文章站
2022-04-10 16:06:27
...
这篇文章主要介绍了ajax实现远程通信的相关资料,对ajax感兴趣的小伙伴们可以参考一下ajax实现远程通信文章
本文实例为大家分享了ajax实现远程通信,供大家参考,具体内容如下
第一个文件:html
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>ajax解决跨域问题</title> <script src="jquery-3.0.0.min.js" type="text/javascript"></script> </head> <body> <script> $.ajax({ type:"POST", url:"postDemo.php", data:{ "url":"http://192.168.4.101:90/PHPStudy4/server.php", "username":"admin", "password":"admin", },success:function(data){ var result=eval("("+data+")"); console.log(result); } }) </script> </body> </html>
第二个文件:服务器端处理数据
<?php /** * Created by PhpStorm. * User: Administrator * Date: 2016-7-21 * Time: 10:12 */ if ($_SERVER["REQUEST_METHOD"] == "POST") { // echo json_encode(array("111"=>"112")); if (isset($_POST["url"]) && isset($_POST["username"]) && isset($_POST["password"])) { $result = postDemo($_POST["url"], array("username" => $_POST["username"], "password" => $_POST["password"])); echo $result; } else { echo json_encode(array("msg2" => "!!!!!!!!!!!!!!!!!!!!!error!!!!!2")); } } else { echo json_encode(array("msg" => "error!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!")); } function postDemo($url, $data) { $query = http_build_query($data); $options = array( "http" => array( "header" => "Content-type: application/x-www-form-urlencoded\r\n" . "Content-length:" . strlen($query) . "\r\n" . "User-Agent:MyAgent/1.0/r/n", "method" => "POST", "content" => $query ) ); $content = stream_context_create($options); $result = file_get_contents($url, false, $content); return $result; } //echo postDemo("http://192.168.4.101:90/PHPStudy4/server.php",array("username"=>"admin","password"=>"admin"));
其中"url":"http://192.168.4.101:90/PHPStudy4/server.php",这个url就是我们向远端的访问地址.
相关推荐:
以上就是ajax实现远程通信的详细内容,更多请关注其它相关文章!