RuntimeError: Output 0 of SelectBackward is a view and is being modified inplace.
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2022-03-04 14:21:27
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1. 问题背景
今天在浏览一些代码的时候,总是出现了以下的错误描述
RuntimeError: Output 0 of SelectBackward is a view and is being modified inplace. This view is the output of a function that returns multiple views. Such functions do not allow the output views to be modified inplace. You should replace the inplace operation by an out-of-place one.
我发现错误的地方都是循环中直接修改原数组导致的:
for next_token_logit in next_token_logits:
next_token_logit[tokenizer.convert_tokens_to_ids('[UNK]')] = -float('Inf')
解释:
在for循环运行的过程中,next_token_logit 中的元素会被修改,然而下一轮循环还会读取next_token_logits并修改,此时Python无法分辨此时:操作原始的next_token_logits还是在循环一轮修改后的next_token_logits?
2. 解决方案
将最开始的直接修改方法改成对数组的索引,然后根据索引直接修改数组对应的位置,例如
for i in range(len(next_token_logits)):
next_token_logits[i][tokenizer.convert_tokens_to_ids('[UNK]')] = -float('Inf')
最后这样就大功告成啦!!
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