mysql_fetch_row(): supplied argument is not a valid MySQL result resource，何人能解？该如何解决
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2022-04-08 20:37:14
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mysql_fetch_row(): supplied argument is not a valid MySQL result resource，何人能解？
代码如下：
/*
* Created on 2012-1-1
*
* To change the template for this generated file go to
* Window - Preferences - PHPeclipse - PHP - Code Templates
*/
$conn = mysql_connect("localhost","root","") or die ("连接出错");
mysql_select_db("dongxinb",$conn);
$sql="SELECT * FROM 'word'";
$query=mysql_query($sql,$conn);
$row=mysql_fetch_array($query);
echo $row[name];
?>
其中name为dongxinb数据库word表的字段。
错误信息：Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\wamp\www\word\1.php on line 13
其中INSERT能正常插入。
------解决方案--------------------
SQL 错了
修改成
$sql="SELECT * FROM word";
------解决方案--------------------
代码如下：
/*
* Created on 2012-1-1
*
* To change the template for this generated file go to
* Window - Preferences - PHPeclipse - PHP - Code Templates
*/
$conn = mysql_connect("localhost","root","") or die ("连接出错");
mysql_select_db("dongxinb",$conn);
$sql="SELECT * FROM 'word'";
$query=mysql_query($sql,$conn);
$row=mysql_fetch_array($query);
echo $row[name];
?>
其中name为dongxinb数据库word表的字段。
错误信息：Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in D:\wamp\www\word\1.php on line 13
其中INSERT能正常插入。
------解决方案--------------------
SQL 错了
修改成
$sql="SELECT * FROM word";
------解决方案--------------------
- PHP code
| 姓名:{$row['name']} | |
| Message:{$row['words']} | 更新时间:{$row['date']} |
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