mysql_fetch_array() expects parameter 1 to be resource

$host = "localhost";
$user = "root";
$password = "123456";

$connection = mysqli_connect($host,$user,$password);
if(!$connection){
exit('连接mysql数据库失败!');
}

$dbname = "chuanke";

mysqli_select_db($connection,$dbname);

$sql = "SELECT * FROM `user`";
$result = mysqli_query($connection,$sql);

while($row=mysqli_fetch_array($result))
{
echo $row[`UserName`]."
";
}

?>
这时候提示：Notice: Undefined index
然后我把while($row=mysqli_fetch_array($result))改成while($row=mysql_fetch_array($result))
这时候报错变成：mysql_fetch_array() expects parameter 1 to be resource,

回复讨论(解决方案)

开error_report,
ini_setting("display_errors", 1);
每行代码都var_dump一下。你差不多就能定位问题了。


加强debug基础的能力。

while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {

哎 整了半天是自己粗心 echo $row[`UserName`]."
"; [`UserName`]应该是[’UserName‘] 还是谢谢楼上两位的帮助