求这种的算法
程序员文章站
2022-04-07 22:05:10
...
比如我现在有一个数组
当然不止这么几个
我想要输出的结果是:
a
b
c
d
e
f
g
aa
ab
ac
ad
ae
af
ag
ba
bb
bc
bd
be
bf
bg
ca
cb
cc
…………
gaaaaaaa
gaaaaaab
gaaaaaac
gaaaaaad
gaaaaaae
…………
就是把这些字符能组成的字符串都罗列出来
当然不止这么几个
我想要输出的结果是:
a
b
c
d
e
f
g
aa
ab
ac
ad
ae
af
ag
ba
bb
bc
bd
be
bf
bg
ca
cb
cc
…………
gaaaaaaa
gaaaaaab
gaaaaaac
gaaaaaad
gaaaaaae
…………
就是把这些字符能组成的字符串都罗列出来
没问题的,就是要无限个啊。。。
(
[0] => a
[1] => b
[2] => c
[3] => aa
[4] => ab
[5] => ac
[6] => ba
[7] => bb
[8] => bc
[9] => ca
[10] => cb
[11] => cc
[12] => aaa
[13] => aab
[14] => aac
[15] => aba
[16] => abb
[17] => abc
[18] => aca
[19] => acb
[20] => acc
[21] => baa
[22] => bab
[23] => bac
[24] => bba
[25] => bbb
[26] => bbc
[27] => bca
[28] => bcb
[29] => bcc
[30] => caa
[31] => cab
[32] => cac
[33] => cba
[34] => cbb
[35] => cbc
[36] => cca
[37] => ccb
[38] => ccc
[39] => aaaa
[40] => aaab
[41] => aaac
[42] => aaba
[43] => aabb
[44] => aabc
[45] => aaca
[46] => aacb
[47] => aacc
[48] => abaa
[49] => abab
[50] => abac
[51] => abba
[52] => abbb
[53] => abbc
[54] => abca
[55] => abcb
[56] => abcc
[57] => acaa
[58] => acab
[59] => acac
[60] => acba
[61] => acbb
[62] => acbc
[63] => acca
[64] => accb
[65] => accc
[66] => baaa
[67] => baab
[68] => baac
[69] => baba
[70] => babb
[71] => babc
[72] => baca
[73] => bacb
[74] => bacc
[75] => bbaa
[76] => bbab
[77] => bbac
[78] => bbba
[79] => bbbb
[80] => bbbc
[81] => bbca
[82] => bbcb
[83] => bbcc
[84] => bcaa
[85] => bcab
[86] => bcac
[87] => bcba
[88] => bcbb
[89] => bcbc
[90] => bcca
[91] => bccb
[92] => bccc
[93] => caaa
[94] => caab
[95] => caac
[96] => caba
[97] => cabb
[98] => cabc
[99] => caca
[100] => cacb
[101] => cacc
[102] => cbaa
[103] => cbab
[104] => cbac
[105] => cbba
[106] => cbbb
[107] => cbbc
[108] => cbca
[109] => cbcb
[110] => cbcc
[111] => ccaa
[112] => ccab
[113] => ccac
[114] => ccba
[115] => ccbb
[116] => ccbc
[117] => ccca
[118] => cccb
[119] => cccc
)
Array
(
[0] => a
[1] => b
[2] => c
[3] => aa
[4] => ab
[5] => ac
[6] => ba
[7] => bb
[8] => bc
[9] => ca
[10] => cb
[11] => cc
)
$array=Array("a",'b','c','d','e','f','g');
当然不止这么几个
我想要输出的结果是:
a
b
c
d
e
f
g
aa
ab
ac
ad
ae
af
ag
ba
bb
bc
bd
be
bf
bg
ca
cb
cc
…………
gaaaaaaa
gaaaaaab
gaaaaaac
gaaaaaad
gaaaaaae
…………
就是把这些字符能组成的字符串都罗列出来
回复讨论(解决方案)
LZ的问题好像有点歧义吧,比如a这个字母
a算一个 aa算一个 aaa算一个 aaaaaaaaaaaaaaaaaaaaaaaaaa也是一个
要多少是结束啊?
比如我现在有一个数组
$array=Array("a",'b','c','d','e','f','g');
当然不止这么几个
我想要输出的结果是:
a
b
c
d
e
f
g
aa
ab
ac
ad
ae
af
ag
ba
bb
bc
bd
be
bf
bg
ca
cb
cc
…………
gaaaaaaa
gaaaaaab
gaaaaaac
gaaaaaad
gaaaaaae
…………
就是把这些字符能组成的字符串都罗列出来
没问题的,就是要无限个啊。。。
$array=Array("a",'b','c','d','e','f','g');
for($i=-1;$i
echo $array[$i].$v."
";
}
}
希望能帮到你~
那您这程序啥时候停止啊....
没问题的,就是要无限个啊。。。
那您这程序啥时候停止啊....
没问题的,就是要无限个啊。。。
拔下电源的时候...
估计是想做对撞机
那您这程序啥时候停止啊....
没问题的,就是要无限个啊。。。
拔下电源的时候...
虽然楼主需求看上去有些无厘头,但如果设定好终止条件也并非不能实现
在有限个数的前提下,这个算法还是很具挑战性的
我先来的抛砖引玉
$ar = array("a",'b','c');print_r(allot($ar, 4));print_r(allot($ar, 2));function allot($ar, $num) { static $st = array(); //用于缓存中间结果 $res = array(); //用于承载返回结果 if(! $st) { $t = $ar; }else { $t = array(); foreach($ar as $v) { $t = array_merge($t, array_map( function($item, $prefix) { return $prefix . $item; }, $st, array_fill(0, count($st), $v))); } }// foreach($t as $v) echo $v . PHP_EOL; //直接产生输出 $res = $st = $t; if($num > 1) $res = array_merge($res, allot($ar, $num-1)); else $st = array(); //初始缓存,以便下一次调用 return $res;}Array
(
[0] => a
[1] => b
[2] => c
[3] => aa
[4] => ab
[5] => ac
[6] => ba
[7] => bb
[8] => bc
[9] => ca
[10] => cb
[11] => cc
[12] => aaa
[13] => aab
[14] => aac
[15] => aba
[16] => abb
[17] => abc
[18] => aca
[19] => acb
[20] => acc
[21] => baa
[22] => bab
[23] => bac
[24] => bba
[25] => bbb
[26] => bbc
[27] => bca
[28] => bcb
[29] => bcc
[30] => caa
[31] => cab
[32] => cac
[33] => cba
[34] => cbb
[35] => cbc
[36] => cca
[37] => ccb
[38] => ccc
[39] => aaaa
[40] => aaab
[41] => aaac
[42] => aaba
[43] => aabb
[44] => aabc
[45] => aaca
[46] => aacb
[47] => aacc
[48] => abaa
[49] => abab
[50] => abac
[51] => abba
[52] => abbb
[53] => abbc
[54] => abca
[55] => abcb
[56] => abcc
[57] => acaa
[58] => acab
[59] => acac
[60] => acba
[61] => acbb
[62] => acbc
[63] => acca
[64] => accb
[65] => accc
[66] => baaa
[67] => baab
[68] => baac
[69] => baba
[70] => babb
[71] => babc
[72] => baca
[73] => bacb
[74] => bacc
[75] => bbaa
[76] => bbab
[77] => bbac
[78] => bbba
[79] => bbbb
[80] => bbbc
[81] => bbca
[82] => bbcb
[83] => bbcc
[84] => bcaa
[85] => bcab
[86] => bcac
[87] => bcba
[88] => bcbb
[89] => bcbc
[90] => bcca
[91] => bccb
[92] => bccc
[93] => caaa
[94] => caab
[95] => caac
[96] => caba
[97] => cabb
[98] => cabc
[99] => caca
[100] => cacb
[101] => cacc
[102] => cbaa
[103] => cbab
[104] => cbac
[105] => cbba
[106] => cbbb
[107] => cbbc
[108] => cbca
[109] => cbcb
[110] => cbcc
[111] => ccaa
[112] => ccab
[113] => ccac
[114] => ccba
[115] => ccbb
[116] => ccbc
[117] => ccca
[118] => cccb
[119] => cccc
)
Array
(
[0] => a
[1] => b
[2] => c
[3] => aa
[4] => ab
[5] => ac
[6] => ba
[7] => bb
[8] => bc
[9] => ca
[10] => cb
[11] => cc
)
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