求一个数组算法
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2022-04-07 19:16:25
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根据 “数组1” 和 “数组2”,得到 “数组3”这样的结果,而且最好能高效点
数组2是设置好的一些属性;数组1是商品可能只填写了某个或某几个属性
数组2是设置好的一些属性;数组1是商品可能只填写了某个或某几个属性
//数组1Array( [100008] => Array ( [5] => Array ( [name] => 价格 [0] => 不限 ) [6] => Array ( [name] => 折扣 [0] => 不限 ) ) [100009] => Array ( [5] => Array ( [name] => 价格 [8] => 0-29 ) [6] => Array ( [name] => 折扣 [13] => 3-5折 ) [7] => Array ( [name] => 出版社 [20] => 北京大学出版社 ) ))//数组2Array( [0] => Array ( [attr_id] => 5 [attr_name] => 价格 [attr_value] => 0-29,30-49,50-99,100以上 ) [1] => Array ( [attr_id] => 6 [attr_name] => 折扣 [attr_value] => 0-3折,3-5折,5-7折,7-10折 ) [2] => Array ( [attr_id] => 7 [attr_name] => 出版社 [attr_value] => ))//得到结果:数组3Array( [100008] => Array ( [价格] => 不限 [折扣] => 不限 [出版社] => ) [100009] => Array ( [价格] => 0-29 [折扣] => 3-5折 [出版社] => 北京大学出版社 ))
回复讨论(解决方案)
$a = array ( 100008 => array ( 5 => array ( 'name' => '价格', 0 => '不限', ), 6 => array ( 'name' => '折扣', 0 => '不限', ), ), 100009 => array ( 5 => array ( 'name' => '价格', 8 => '0-29', ), 6 => array ( 'name' => '折扣', 13 => '3-5折', ), 7 => array ( 'name' => '出版社', 20 => '北京大学出版社', ), ),);$b = array ( 0 => array ( 'attr_id' => '5', 'attr_name' => '价格', 'attr_value' => '0-29,30-49,50-99,100以上', ), 1 => array ( 'attr_id' => '6', 'attr_name' => '折扣', 'attr_value' => '0-3折,3-5折,5-7折,7-10折', ), 2 => array ( 'attr_id' => '7', 'attr_name' => '出版社', 'attr_value' => '', ),);foreach($a as $key=>$item) { $t = array(); foreach($b as $v) { $k = $v['attr_id']; $t[$v['attr_name']] = isset($item[$k]) ? end($item[$k]) : $v['attr_value']; } $c[$key] = $t;}print_r($c);
Array( [100008] => Array ( [价格] => 不限 [折扣] => 不限 [出版社] => ) [100009] => Array ( [价格] => 0-29 [折扣] => 3-5折 [出版社] => 北京大学出版社 ))
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