基于EazyX实现五子棋小游戏（人人对战）

写完了才发现棋子应该落在交点处，但是懒得改了，有兴趣的话修改一下相关坐标即可，还有就是代码可能有些臃肿，对于代码重用做的不是很好，可以优化一下

#include <cstdio>
#include <conio.h>
#include <iostream>
#include <graphics.h>
#define Graph_Size 750  //定义窗口大小
using namespace std;
const int Size = 15;  //棋盘为15*15
const int Average = Graph_Size / Size;  //每一个格子的大小
int vis[Size + 5][Size + 5];  //记录棋盘每个格子里面是否有棋子
inline void DrawMap() {  //背景初始化
	initgraph(Graph_Size, Graph_Size);  //初始化750*750窗口
	setbkcolor(YELLOW);  //背景颜色为黄色
	cleardevice(); //清空绘图设备
	setcolor(BLACK);  //设置当前绘图前景色
	setfillcolor(BLACK);  //设置当前设备填充颜色为黑色
	settextstyle(Average, Average, _T("宋体"));  //设置字体大小和字体样式
	for (int i = Average; i < Graph_Size; i += Average) {  //画横线
		line(i, 0, i, Graph_Size);
	}
	for (int i = Average; i < Graph_Size; i += Average) {  //画纵线
		line(0, i, Graph_Size, i);
	}
}
inline int judge() {  //判断游戏是否结束
	for (int i = 0; i < Size; ++i) {  //是否有横着的5个相同的棋子
		int j = 0;
		while (j < Size) {
			int Victory_Black = 5;
			int Victory_White = 5;
			while (j < Size && !vis[i][j]) ++j;
			while (j < Size && vis[i][j] == 1) {
				--Victory_Black;
				++j;
			}
			if (Victory_Black <= 0) return 1;
			while (j < Size && vis[i][j] == 2) {
				--Victory_White;
				++j;
			}
			if (Victory_White <= 0) return 2;
		}
	}
	for (int i = 0; i < Size; ++i) { //是否有纵着的5个相同的棋子
		int j = 0;
		while (j < Size) {
			int Victory_Black = 5;
			int Victory_White = 5;
			while (j < Size && !vis[j][i]) ++j;
			while (j < Size && vis[j][i] == 1) {
				--Victory_Black;
				++j;
			}
			if (Victory_Black <= 0) return 1;
			while (j < Size && vis[j][i] == 2) {
				--Victory_White;
				++j;
			}
			if (Victory_White <= 0) return 2;
		}
	}
	for (int i = 0; i < Size; ++i) { //是否有左右对角线的5个相同的棋子
		for (int j = Size - 1; j >= 0; --j) {
			int k = 0;
			while (i + k < Size && j + k < Size) {
				int Victory_Black = 5;
				int Victory_White = 5;
				while (i + k < Size && j + k < Size && !vis[i + k][j + k]) ++k;
				while (i + k < Size && j + k < Size && vis[i + k][j + k] == 1) {
					--Victory_Black;
					++k;
				}
				if (Victory_Black <= 0) return 1;
				while (i + k < Size && j + k < Size && vis[i + k][j + k] == 2) {
					--Victory_White;
					++k;
				}
				if (Victory_White <= 0) return 2;
			}
		}
	}
	for (int i = 0; i < Size; ++i) { //是否有右左对角线的5个相同的棋子
		for (int j = 0; j < Size; ++j) {
			int k = 0;
			while (i + k < Size && j - k >= 0) {
				int Victory_Black = 5;
				int Victory_White = 5;
				while (i + k < Size && j - k >= 0 && !vis[i + k][j - k]) ++k;
				while (i + k < Size && j - k >= 0 && vis[i + k][j - k] == 1) {
					--Victory_Black;
					++k;
				}
				if (Victory_Black <= 0) return 1;
				while (i + k < Size && j - k >= 0 && vis[i + k][j - k] == 2) {
					--Victory_White;
					++k;
				}
				if (Victory_White <= 0) return 2;
			}
		}
	}
	return 0;
}
int main() {
	DrawMap();  //画背景
	bool Black_Or_White = false; //false表示黑棋下，true表示白棋下
	while (true) {
		MOUSEMSG msg;
		msg = GetMouseMsg();
		if (msg.uMsg == WM_LBUTTONDOWN) {  //根据鼠标落下的坐标画黑白棋子
			if (vis[msg.x / Average][msg.y / Average]) continue;
			if (!Black_Or_White) {
				setfillcolor(BLACK);
				fillcircle((msg.x / Average) * Average + Average / 2, (msg.y / Average) * Average + Average / 2, Average / 2);
				IMAGE img((msg.x / Average) * Average + Average / 2, (msg.y / Average) * Average + Average / 2);
				SetWorkingImage(&img);
				setfillstyle(BS_PATTERN, NULL, &img);
				SetWorkingImage(NULL);
				Black_Or_White = true;
				vis[msg.x / Average][msg.y / Average] = 1;
			}
			else {
				setfillcolor(WHITE);
				fillcircle((msg.x / Average) * Average + Average / 2, (msg.y / Average) * Average + Average / 2, Average / 2);
				IMAGE img((msg.x / Average) * Average + Average / 2, (msg.y / Average) * Average + Average / 2);
				SetWorkingImage(&img);
				setfillstyle(BS_PATTERN, NULL, &img);
				SetWorkingImage(NULL);
				Black_Or_White = false;
				vis[msg.x / Average][msg.y / Average] = 2;
			}
			int If_Over = judge();  //0表示游戏继续，1表示黑棋胜，2表示白棋胜利
			if (!If_Over) continue;
			outtextxy(Average * 2, Average * 7, If_Over == 1 ? _T("Black  Win!") : _T("White  Win!"));
			break;
		}
	}
	_getch();  //按任意键退出
	closegraph();  //关闭窗口
	return 0;
}