python比较2个xml内容的方法
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2022-04-04 19:43:31
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本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下:
from xml.etree import ElementTree OK=True main_pid = 10000 loop_depth = 0 def compare_xml(left, right, key_info='.'): global loop_depth loop_depth += 1 if loop_depth == 1: print if left.tag != right.tag: print_diff(main_pid, key_info, 'difftag', left.tag, right.tag) return if left.text != right.text: print_diff(main_pid, key_info, 'difftext', left.text, right.text) return leftitems = dict(left.items()) rightitems = dict(right.items()) for k,v in leftitems.items(): if k not in rightitems: s = '%s/%s' % (key_info, left.tag) print_diff(main_pid, s, 'lostattr', k, "") for k,v in rightitems.items(): if k not in leftitems: s = '%s/%s' % (key_info, right.tag) print_diff(main_pid, s, 'extraattr', "", k) leftnodes = left.getchildren() rightnodes = right.getchildren() leftlen = len(leftnodes) rightlen = len(rightnodes) if leftlen != rightlen: s = '%s/%s' % (key_info, right.tag) print_diff(main_pid, s, 'difflen', leftlen, rightlen) return l = leftlen%-40s [ %s != %s ]'%(msg.upper(), main_pid, key_info.strip('./'), base_type, test_type) print info.encode('gbk') OK = False
调用:
if __name__ == '__main__': s1 = ''''' \\ ''' s2 = ''''' \\ \linux \30 \\ \windows \20 \\ ''' lroot = ElementTree.fromstring(s1) rroot = ElementTree.fromstring(s2) compare_xml(lroot, rroot)\ \windows \20 \\ \linux \30 \
希望本文所述对大家的Python程序设计有所帮助。
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