C语言实现双人五子棋游戏

本文实例为大家分享了c语言实现双人五子棋游戏的具体代码，供大家参考，具体内容如下

实现功能

生成棋盘玩家1与玩家2对战，哪个玩家率先有连续5子连线，哪个玩家赢。

如何实现

组成：

二维数组：board[row][col],定义一个row*col的棋盘。

主要逻辑：

显示棋盘，提示用户下子，下子后判断

1.显示棋盘很简单，慢慢凑棋盘就好
2. 用户下子，注意两个条件：棋子在棋盘里，下子位置未被占用。
3.判断是最难的，

方法：从下子位置的8个方向(上，下，左，右，右上，右下，左上，左下)计算相同棋子数目，然后将对角的棋子数相加,等于5说明有5子连线

主要函数中用到三个主要实现函数：

showboard(board, row, col)；//展示棋盘
playermove(board, row, col, cur);//玩家下注，cur表示哪个玩家下子
judge(board, row, col);//判断5子连线
getcount(board[][col], row, col, dir)//计算方向dir相同棋子数

代码

头文件

#ifndef __fivechree_h__
#define __fivechee_h__


#include<stdio.h>
#include<windows.h>
#pragma warning(disable:4996)

#define row 10//棋盘行数
#define col 10//棋盘列数
#define init '*'//棋盘初始化

#define player1 1
#define player2 2
#define next 3//继续往下下
#define draw 4//棋盘下满 平局

//8个方向
#define up 10
#define right_up 11
#define right 12
#define right_down 13
#define down 14
#define left_down 15
#define left 16
#define left_up 17

extern void menu();
extern void game();

#endif

main函数源文件

#include"fivechree.h"
int main(){
 int quit = 0;
 while (!quit){
  menu();
  int select = 0;
  scanf("%d", &select);
  switch (select){
  case 1:
   game();
   break;
  case 2:
   quit = 1;
   break;
  default:
   printf("enter error!\n");
   break;
   
  }

 }
 printf("byebye\n");
 system("pause");
 return 0;
}

函数定义源文件

#include"fivechree.h"

static int x = 0;
static int y = 0;

void menu(){
 printf("+---------------------+\n");
 printf("+- 1.play    2.exit  -+\n");
 printf("+---------------------+\n");
 printf("please enter your select#");

}
static void showboard(int board[][col], int row, int col){//展示棋盘 o玩家1棋子，x玩家2棋子
 system("cls");
 for (int i = 0; i < row; i++){
  for (int j = 0; j < col; j++){
   switch (board[i][j]){
   case player1:
    board[i][j] = 'o';
    break;
   case player2:
    board[i][j] = 'x';
    break;
   case 0:
    board[i][j] = init;
    break;
   default:
    break;
   }
  }
 }
 printf("  ");
 for (int i =1; i <= row; i++){
  printf("%2d ", i);
 }
 printf("\n");
 for (int i = 1; i <= row; i++){
  printf("%-2d", i);
  for (int j = 1; j <= col; j++){
   printf(" %c ", board[i - 1][j - 1]);
  }
  printf("\n");
 }
}

static void playermove(int board[][col], int row, int col, int who){//玩家下子，who 为哪个玩家下子
 while (1){
  printf("please enter player%d postion<x,y>#", who);
  scanf("%d %d", &x, &y);
  if (x<1 || x>row || y<1 || y>col){  //超过棋盘范围
   printf("postion is error!\n");
   continue;
  }
  if (board[x - 1][y - 1] == init){//判断位置是否已被下子
   board[x - 1][y - 1] = who;
   break;
  }
  printf("postion is not empty\n");
 }

}

static int getcount(int board[][col], int row, int col, int dir){//判断8个方向相同棋子的数目
 int _x = x;//_x,_y变化，后面与x，y棋子相比较
 int _y = y;
 int count = 0;
 while (1){
  switch (dir){
  case up:
   _x--;
   break;
  case down:
   _x++;
   break;
  case left:
   _y--;
   break;
  case right:
   _y++;
   break;
  case right_up:
   _x--, _y++;
   break;
  case right_down:
   _x++, _y++;
   break;
  case left_down:
   _x++, _y--;
   break;
  case left_up:
   _x--, _y--;
   break;
  default:
   break;
  }
  if (_x>=1 || _x<=row || _y>=1 || _y<=col){//棋子不能越界
   if (board[x-1][y-1] == board[_x-1][_y-1]){
    //printf("yes\n");
    count++;
   }
   else{
    //printf("no\n");
    break;
   }
  }
  else{
   return count;
  }
  
 }
 return count;
}
//如何判断：从下子位置的8个方向(上，下，左，右，右上，右下，左上，左下)
//计算相同棋子数目，然后将对角的棋子数相加,等于5说明有5子连线
static int judge(int board[][col], int row, int col){
 int count1 = getcount(board, row, col, up)\
  + getcount(board, row, col, down);
 //printf("%d\n", count1);
 if (count1 >= 4){
  return board[x-1][y-1];
 }
 count1 = getcount(board, row, col, right_up)\
  + getcount(board, row, col, left_down);
 //printf("%d\n", count1);
 if (count1 >= 4){
  return board[x-1][y-1];
 }
 count1 = getcount(board, row, col, right)\
  + getcount(board, row, col, left);
 //printf("%d\n", count1);
 if (count1 >= 4){
  return board[x-1][y-1];
 }
 count1 = getcount(board, row, col, right_down)\
  + getcount(board, row, col, left_up);
 if (count1 >= 4){
  return board[x-1][y-1];
 }

 for (int i = 0; i < row; i++){//判断棋盘是否下满
  for (int j = 0; j < col; j++){
   if (board[i][j] == init){
    return next;
   }
  }
 }
 return draw;
}


void game(){
 int board[row][col] = { 0 };
 //memset(board, init, row*col);
 int result = 0;
 int cur = player1;
 showboard(board, row, col);//先展示棋盘
 while (1){
  //showboard(board, row, col);
  playermove(board, row, col, cur);
  showboard(board, row, col);//棋盘将board数组变化，所以要在判断前将数组变化
  result = judge(board, row, col);
  if (result != next){
   break;
  }
  cur = (cur == player1 ? player2 : player1);//三目表达式，注意不是 player1 ? player2 : player1
 }

 showboard(board, row, col);
 switch (result){
 case 'o':
  printf("player1 win!\n");
  break;
 case 'x':
  printf("player2 win!\n");
  break;
 case draw:
  printf("tie game!\n");
  break;
 default:
  //printf("%c\n", result);
  printf("bug\n");
  break;
 }
}

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