PHP正则验证Email的方法
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2022-03-31 18:25:27
本文实例讲述了php正则验证email的方法。分享给大家供大家参考。具体如下:
本文实例讲述了php正则验证email的方法。分享给大家供大家参考。具体如下:
<?php function validateemail($email) { $isvalid = true; $atindex = strrpos($email, "@"); if (is_bool($atindex) && !$atindex) { $isvalid = false; } else { $domain = substr($email, $atindex+1); $local = substr($email, 0, $atindex); $locallen = strlen($local); $domainlen = strlen($domain); if ($locallen < 1 || $locallen > 64) { // local part length exceeded $isvalid = false; } else if ($domainlen < 1 || $domainlen > 255) { // domain part length exceeded $isvalid = false; } else if ($local[0] == '.' || $local[$locallen-1] == '.') { // local part starts or ends with '.' $isvalid = false; } else if (preg_match('/\\.\\./', $local)) { // local part has two consecutive dots $isvalid = false; } else if (!preg_match('/^[a-za-z0-9\\-\\.]+$/', $domain)) { // character not valid in domain part $isvalid = false; } else if (preg_match('/\\.\\./', $domain)) { // domain part has two consecutive dots $isvalid = false; } else if(!preg_match('/^(\\\\.|[a-za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/', str_replace("\\\\","",$local))) { // character not valid in local part unless // local part is quoted if (!preg_match('/^"(\\\\"|[^"])+"$/', str_replace("\\\\","",$local))) { $isvalid = false; } } if ($isvalid && !(checkdnsrr($domain,"mx") || checkdnsrr($domain,"a"))) { // domain not found in dns $isvalid = false; } } return $isvalid; } ?>
ps:这里再为大家提供2款非常方便的正则表达式工具供大家参考使用:
javascript正则表达式在线测试工具:
正则表达式在线生成工具:
希望本文所述对大家的php程序设计有所帮助。
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