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python3 set(集合)详解

程序员文章站 2022-03-30 12:30:30
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add(增加元素)
name = set(['Tom','Lucy','Ben'])
name.add('Juny')print(name)#输出:{'Lucy', 'Juny', 'Ben', 'Tom'}

clear(清空所有元素)

name = set(['Tom','Lucy','Ben'])
name.clear()print(name)#输出:set()

copy(拷贝set集合)

name = set(['Tom','Lucy','Ben'])
new_name = name.copy()print(new_name)#输出:{'Tom', 'Lucy', 'Ben'}

difference(返回两个或多个集合中不同的元素,并生成新的集合)

A = set([2,3,4,5])
B = set([3,4])
C = set([2])
n = n1.difference(n2,n3)
print(n)
#输出:{5}
#返回A集合里面,在B和C集合中没有的元素,并生成新的集合

difference_update删除A集合里面,在B集合中存在的元素。)

A = set([2,3,4,5])
B = set([4,5])
A.difference_update(B)
print(A)

#输出:{2, 3}

discard(移除元素)

n = set([2,3,4])
n.discard(3)print(n)#输出:{2, 4}

intersection(取交集,并生成新的集合)

n1 = set([2,3,4,5])
n2 = set([4,5,6,7])
n = n1.intersection(n2)print(n)#输出:{4, 5}

intersection_update(取交集,修改原来的集合)

n1 = set([2,3,4,5])
n2 = set([4,5,6,7])
n1.intersection_update(n2)print(n1)#输出:{4, 5}

isdisjoint(判断交集,是返回False,否返回True)

n1 = set([2,3,4,5])
n2 = set([4,5,6,7])print(n1.isdisjoint(n2))#输出:False

issubset(判断子集)

A = set([2,3])
B = set([2,3,4,5])print(A.issubset(B))#输出:True#A是B的子集

issuperset(判断父集)

A = set([2,3])
B = set([2,3,4,5])print(B.issuperset(A))# 输出:True#B是A的父集

pop(随机移除一个元素)

n = set([2,3,4,5])
n1 = n.pop()print(n,n1)# 输出:{3, 4, 5} 2

remove(移除指定元素)

n = set([2,3,4,5])
n.remove(2)print(n)# 输出:{3, 4, 5}

symmetric_difference(取交集,并生成新的集合)

A = set([2,3,4,5])
B = set([4,5,6,7])print(A.symmetric_difference(B))# 输出:{2, 3, 6, 7}

symmetric_difference_update(取交集,改变原来的集合)

A = set([2,3,4,5])
B = set([4,5,6,7])
A.symmetric_difference_update(B)print(A)# 输出:{2, 3, 6, 7}

union(取并集,并生成新的集合)

A = set([2,3,4,5])
B = set([4,5,6,7])print(A.union(B))# 输出:{2, 3, 4, 5, 6, 7}

update(取并集,改变原来的集合)

A = set([2,3,4,5])
B = set([4,5,6,7])
A.update(B)print(A)# 输出:{2, 3, 4, 5, 6, 7}

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