postgresql 计算两点距离的2种方法小结
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2022-03-30 11:31:58
postgresql计算两点距离下面两种方法:select st_distance( st_setsrid(st_makepoint(115.97166453999147,28.71649391423...
postgresql计算两点距离
下面两种方法:
select st_distance( st_setsrid(st_makepoint(115.97166453999147,28.716493914230423),4326)::geography, st_setsrid(st_makepoint(106.00231199774656,29.719258550486572),4326)::geography ), st_length( st_makeline( st_makepoint(115.97166453999147,28.716493914230423), st_makepoint(106.00231199774656,29.719258550486572) )::geography )
备注:
st_geomfromtext('linestring(115.97166453999147 28.716493914230423,106.00231199774656 29.719258550486572)')与 st_makeline( st_makepoint(115.97166453999147,28.716493914230423), st_makepoint(106.00231199774656,29.719258550486572) )等价 st_geomfromtext('point(115.97166453999147 28.716493914230423)',4326)与 st_setsrid(st_makepoint(115.97166453999147,28.716493914230423),4326)等价 st_setsrid(st_makepoint(115.97166453999147,28.716493914230423),4326)::geography与 geography(st_setsrid(st_makepoint(115.97166453999147,28.716493914230423),4326))、 st_geographyfromtext('srid=4326;point(115.97166453999147 28.716493914230423)')等价 (::geography是postgis中的转换类型语法,把geometry转成geography)
补充:postgresql计算两点欧式距离(经纬度地理位置)
我就废话不多说了,大家还是直接看代码吧~
create or replace function getdistance ( lon1 numeric, lat1 numeric, lon2 numeric, lat2 numeric ) returns int as $body$ declare v_distance numeric; v_earth_radius numeric; radlat1 numeric; radlat2 numeric; v_radlatdiff numeric; v_radlngdiff numeric; begin --地球半径 v_earth_radius:=6378137; radlat1 := lat1 * pi()/180.0; radlat2 := lat2 * pi()/180.0; v_radlatdiff := radlat1 - radlat2; v_radlngdiff := lon1 * pi()/180.0 - lon2 * pi()/180.0; v_distance := 2 * asin(sqrt(power(sin(v_radlatdiff / 2), 2) + cos(radlat1) * cos(radlat2) * power(sin(v_radlngdiff/2),2))); v_distance := round(v_distance * v_earth_radius); return v_distance; end; $body$ language 'plpgsql' volatile;
create or replace function getdistance ( i_lngbegin real, i_latbegin real, i_lngend real, i_latend real ) returns float as $body$ /* * * select getdistance_bygispoint(116.281524,39.957202,117.648673,38.42584) as distance; * */ declare v_distance real; v_earth_radius real; v_radlatbegin real; v_radlatend real; v_radlatdiff real; v_radlngdiff real; begin --地球半径 v_earth_radius:=6378.137; v_radlatbegin := i_latbegin * pi()/180.0; v_radlatend := i_latend * pi()/180.0; v_radlatdiff := v_radlatbegin - v_radlatend; v_radlngdiff := i_lngbegin * pi()/180.0 - i_lngend * pi()/180.0; v_distance := 2 * asin(sqrt(power(sin(v_radlatdiff / 2), 2) + cos(v_radlatbegin) * cos(v_radlatend) * power(sin(v_radlngdiff/2),2))); v_distance := v_distance * v_earth_radius*1000; return v_distance; end; $body$ language 'plpgsql' volatile;
以上为个人经验,希望能给大家一个参考,也希望大家多多支持。如有错误或未考虑完全的地方,望不吝赐教。
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