如何把字符串转化成时间
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2022-03-29 08:04:24
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在python中,日期、时间、字符串的相互转换。
(1)可以将dateTime转换为date,date不能直接转换为dateTime
import datetime dateTime_p = datetime.datetime.now() date_p = dateTime_p.date() print(dateTime_p) #2019-01-30 15:17:46.573139 print(date_p) #2019-01-30
(2)日期类型date转换为字符串str
#!/usr/bin/env python3 import datetime date_p = datetime.datetime.now().date() str_p = str(date_p) print(date_p,type(date_p)) #2019-01-30 <class 'datetime.date'> print(str_p,type(str_p)) #2019-01-30 <class 'str'>
(3)字符串类型str转换为dateTime类型
import datetime str_p = '2019-01-30 15:29:08' dateTime_p = datetime.datetime.strptime(str_p,'%Y-%m-%d %H:%M:%S') print(dateTime_p) # 2019-01-30 15:29:08
(4)dateTime类型转为str类型
import datetime dateTime_p = datetime.datetime.now() str_p = datetime.datetime.strftime(dateTime_p,'%Y-%m-%d') print(dateTime_p) # 2019-01-30 15:36:19.415157
(5)字符串类型str转换为date类型
#!/usr/bin/env python3 import datetime str_p = '2019-01-30' date_p = datetime.datetime.strptime(str_p,'%Y-%m-%d').date() print(date_p,type(date_p)) # 2019-01-30 <class 'datetime.date'>
另外dateTime类型和date类型可以直接做加1减1这种操作
#!/usr/bin/env python3 import datetime # today = datetime.datetime.today() today = datetime.datetime.today().date() yestoday = today + datetime.timedelta(days=-1) tomorrow = today + datetime.timedelta(days=1) print(today) # 2019-01-30 print(yestoday)# 2019-01-29 print(tomorrow)# 2019-01-31
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