Mysql排序获取排名的实例代码

代码如下所示：

select @i:=@i+1 rownum,
if(@total=t.s_score,@rank,@rank:=@i) rank,@total:=t.s_score,
t.*
from(
select t1.* ,t2.s_score from student t1 left join score t2 on t1.s_id=t2.s_id and t2.c_id="01" order by t2.s_score desc
)t,(select @i:=0,@rank:=0,@total:=null) s ;
select @i:=@i+1 rownum,
if(@total=t.s_score,@rank,@rank:=@rank+1) rank,@total:=t.s_score,
t.*
from(
select t1.* ,t2.s_score from student t1 left join score t2 on t1.s_id=t2.s_id and t2.c_id="01" order by t2.s_score desc
)t,(select @i:=0,@rank:=0,@total:=null) s ; 

mysql 获取成绩排序后的名次

其实就是输出mysql的排序后的行号

rt：获取单个用户的成绩在所有用户成绩中的排名

可以分两步：

1、查出所有用户和他们的成绩排名

select id,maxscore,(@rownum:=@rownum+1) as rowno 
from t_user, 
(select (@rownum :=0) ) b 
order by t_user.maxscore desc  

2、查出某个用户在所有用户成绩中的排名

select u.rowno from ( 
select id,(@rownum:=@rownum+1) as rowno 
from t_user, 
(select (@rownum :=0) ) b 
order by t_user.maxscore desc ) u where u.id="2015091810371700001"; 

总结

以上所述是小编给大家介绍的mysql排序获取排名，希望对大家有所帮助