SQL数据库十四种案例介绍
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2022-03-02 23:11:08
数据表/*navicat sqlite data transfersource server : schoolsource server version : 30808source h...
数据表
/* navicat sqlite data transfer source server : school source server version : 30808 source host : :0 target server type : sqlite target server version : 30808 file encoding : 65001 date: 2021-12-23 16:06:04 */ pragma foreign_keys = off; -- ---------------------------- -- table structure for course -- ---------------------------- drop table if exists "main"."course"; create table course( courseid integer primary key autoincrement, courseme varchar(32), teacherid int ); -- ---------------------------- -- records of course -- ---------------------------- insert into "main"."course" values (3001, '语文', 1001); insert into "main"."course" values (3002, '数学', 1002); -- ---------------------------- -- table structure for mark -- ---------------------------- drop table if exists "main"."mark"; create table mark( userid integer, courseid integer not null, score int default 0 ); -- ---------------------------- -- records of mark -- ---------------------------- insert into "main"."mark" values (2001, 3001, 89); insert into "main"."mark" values (2001, 3002, 90); insert into "main"."mark" values (2002, 3001, 66); insert into "main"."mark" values (2003, 3002, 85); -- ---------------------------- -- table structure for sqlite_sequence -- ---------------------------- drop table if exists "main"."sqlite_sequence"; create table sqlite_sequence(name,seq); -- ---------------------------- -- records of sqlite_sequence -- ---------------------------- insert into "main"."sqlite_sequence" values ('teacher', 1002); insert into "main"."sqlite_sequence" values ('student', 2002); insert into "main"."sqlite_sequence" values ('course', 3002); -- ---------------------------- -- table structure for student -- ---------------------------- drop table if exists "main"."student"; create table student( userid integer primary key autoincrement, username varchar(32), userage int, usersex varchar(32) ); -- ---------------------------- -- records of student -- ---------------------------- insert into "main"."student" values (2001, '小明', 18, '男'); insert into "main"."student" values (2002, '小红', 18, '女'); -- ---------------------------- -- table structure for teacher -- ---------------------------- drop table if exists "main"."teacher"; create table teacher( teacherid integer primary key autoincrement, teachername varchar(32) ); -- ---------------------------- -- records of teacher -- ---------------------------- insert into "main"."teacher" values (1001, '张三'); insert into "main"."teacher" values (1002, '李四');
问题:
1、查询“语文”课程比“数学”课程成绩低的所有学生的学号
select a.userid from (select userid,score from mark where courseid ='3001')a, (select userid,score from mark where courseid ='3002')b where a.userid = b.userid and a.score<b.score;
2、查询平均成绩大于60分的同学的学号和平均成绩
select userid,avg(score) from mark group by userid having avg(score)>60;
3、查询所有同学的学号、姓名、选课数、总成绩
select s.userid ,s.username ,count_courseid as 选课数, sum_score as 总成绩 from student s left join (select userid,count(courseid ) as count_courseid,sum(score) as sum_score from mark group by userid )sc on s.userid = sc.userid;
4、查询姓‘李'的老师的个数:
select count(teachername ) from teacher where teachername like '张%';
5、检索语文课程分数小于60,按分数降序排列的同学学号:
select userid ,score from mark where courseid ='3001' and score<60 order by score desc;
6、查询学/没学过”张三”老师讲授的任一门课程的学生姓名
select username from student where userid in ( select userid from mark,course,teacher where course.teacherid = teacher.teacherid and mark.courseid = course.courseid and teacher.teachername ='张三' );
7、查询全部学生选修的课程和课程号和课程名:
select courseid ,courseme from course where courseid in (select courseid from mark group by courseid);
8、检索选修两门课程的学生学号:
select userid from mark group by userid having count(8) == 2;
9、查询各个课程及相应的选修人数
select courseid ,count(*) from course group by courseid ;
10、查询选修“张三”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select student.username ,mark.score from mark left join student on mark.userid = student.userid left join course on mark.courseid = course.courseid left join teacher on course.teacherid = teacher.teacherid where teacher.teachername = '张三' and mark.score = ( select max(score) from mark sc_1 where mark.courseid = sc_1.courseid);
11、求选了课程的学生人数:
select count(2) from (select distinct userid from mark)a;
12、查询课程编号为“语文”且课程成绩在80分以上的学生的学号和姓名
select mark.userid,student.username from mark left join student on mark.userid = student.userid where mark.courseid = '3001' and mark.score>80;
13、查询每门课程的平均成绩,结果按平均成绩升序排序,平均成绩相同时,按课程号降序排列
select courseid ,avg(score) from mark group by courseid order by avg(score),courseid desc;
14、查询课程名称为“数学”,且分数高于85的学生名字和分数:
select c.courseme ,student.userid ,student.username ,mark.score from course c left join mark on mark.courseid = c.courseid left join student on student.userid = mark.userid where c.courseme = '数学' and mark.score>85;
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