欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  后端开发

php判断远程资源是否存在的示例代码分析

程序员文章站 2022-03-26 09:58:02
...
php判断远程资源是否存在的示例代码分析
<?php
$url1='http://www.91hi.net/web/demo/1.jpg' //exists
$url2='http://91hi.net/web/demo/www/jd/image/logo.png'; //not exists 
 
 
 
$get1=get_headers($url1);
$get2=get_headers($url2);
 
print_r($get1);
print_r($get2);

返回结果:

Array
(
    [0] => HTTP/1.1 404 Not Found
    [1] => Date: Tue, 14 Mar 2017 10:58:00 GMT
    [2] => Server: Apache
    [3] => Vary: User-Agent,Accept-Encoding
    [4] => Connection: close
    [5] => Content-Type: text/html
)
Array
(
    [0] => HTTP/1.1 200 OK
    [1] => Date: Tue, 14 Mar 2017 10:58:00 GMT
    [2] => Server: Apache
    [3] => Last-Modified: Wed, 09 Nov 2016 08:57:06 GMT
    [4] => ETag: "2162a05-13f5-540da70f97c80"
    [5] => Accept-Ranges: bytes
    [6] => Content-Length: 5109
    [7] => Vary: User-Agent
    [8] => Connection: close
    [9] => Content-Type: image/png
)
 
可以看到返回的http状态信息组成的一维数组.且第一个数组单元为响应状态信息.

于是乎,通过获取到的状态码,用来判断远程资源是否存在。

$statusCode=substr($get1[0], 9, 3);
if($statusCode == 200 || $statusCode == 304){
    echo "It's exists."
}else{
    echo "It's not exists."
}

以上就是php判断远程资源是否存在的示例代码分析的详细内容,更多请关注其它相关文章!

相关标签: php,远程资源