将json数据提交到action并解析

程序员文章站 2022-03-26 09:53:24

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ajax将json数据提交到action并解析




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Action代码如下：
package controller;

import com.opensymphony.xwork2.ActionSupport;

import net.sf.json.JSONObject;

public class GetJSON extends ActionSupport{
	private String jsonString;
	public String getJsonString(){
		return this.jsonString;
	}
	
	public void setJsonString(String jsonString){
		this.jsonString = jsonString;
	}
	
	@Override
	public String execute() throws Exception {
		System.out.println(jsonString);
		JSONObject json = JSONObject.fromObject(jsonString);
		System.out.println("username=" + json.get("username"));
		System.out.println("password=" + json.get("password"));
		System.out.println("age=" + json.get("age"));
		System.out.println("BigText=" + json.get("BigText"));
		return null;
	}
}