python ATM机 案例代码
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2022-03-25 18:49:31
利用目前学的流程控制写的 ......
利用目前学的流程控制写的
'''
atm机
需求:
1.登陆
输入账号输入密码
每日只有3次登陆密码错误的机会,超过3次禁止登陆
2.查询余额
3.存款
4.取款
5.转帐
6.退出
'''
infos = [
{'name':'jack','pwd':'123','yue':0},
{'name':'bran','pwd':'123','yue':0},
{'name':'egon','pwd':'123','yue':0},
]
# 禁止登陆
ban = false
# 登陆状态
login_state = false
# 账号密码错误次数
login_num = 0
# 菜单 choice
choice = 0
# 输入的用户名
name = ''
# 输入的密码
pwd = ''
# 余额
yue = 0
while ban == false:
# 登陆
while login_state == false:
# 登陆
name = input('请输入账号:')
pwd = input('请输入密码:')
# 查询账号密码是否正确
for info in infos:
if name == info['name'] and pwd == info['pwd']:
print('登陆成功!')
login_state = true
yue = info['yue']
break
# 如果没有账号密码不正确则 运行下面的代码
if login_state == false:
login_num += 1
print('账号密码错误!请重新输入!剩余次数 %s' % (3 - login_num))
if login_num == 3:
print('今日登陆错误次数超限,请明日再来')
ban = true
break
# 打印菜单
if login_state == true and choice == 0:
print('''
1 查询
2 存款
3 转帐
4 取款
5 退出
''')
choice = int(input('请输入操作状态:'))
# 查询
if login_state == true and choice == 1:
print('%s 账户的余额为 %s ¥' % (name,yue))
choice = 0
# 存款
if login_state == true and choice == 2:
money = int(input('请输入你的金额:'))
for info in infos:
if name == info['name']:
info['yue'] += money
yue += money
print('%s 账户存入 %s ¥' % (name,money))
choice = 0
# 转帐:
if login_state == true and choice == 3:
to_state = 0 # 1:成功 2:余额不足
to_num = 0
while to_state == 0:
to_name = input('请输入转入的用户名:')
# 判断 用户是否存在
for info in infos:
if to_name == info['name']:
money = int(input('请输入转帐的金额:'))
# 判断自己账户的金额是否足够
if yue >= money:
info['yue'] += money
yue -= money
print('你给 %s 用户成功转入 %s ¥'%(to_name,money))
to_state = 1
break
else:
print('你的余额不足,请充值后再转帐')
to_state = 2
if to_state == 1:
break
elif to_state == 2:
break
else:
to_num += 1
print('你输入的用户不存在,请重新输入:')
choice = 0
# 取款
if login_state == true and choice == 4:
money = int(input('请输入你的取款金额:'))
# 判断输入的金额是否小于等于余额
if money <= yue:
print('请再出钞口取钞票吧!')
yue -= money
choice = 0
else:
print('你输入的金额大于你的余额,无法取款!')
# 退出
if login_state == true and choice == 5:
break