mysql非占位排名_MySQL

找了好久的mysql排名解决办法，排名结果：1,2,2,3,4,5,5

看sql吧，相信可以看的懂。是从*中找的。

SELECT name,clazz,user_id,class_id,xn,scoreSum,awardedMarks,totalPoint,	CASE	    WHEN @prev_value = totalPoint THEN @rank_count	    WHEN @prev_value := totalPoint THEN @rank_count := @rank_count + 1	END AS rank FROM 	(SELECT au.`NAME` AS NAME,CONCAT(vc.`levelname`,vc.`gradename`,vc.`classname`) AS clazz, cs.user_id,cs.class_id,			cs.`xn`,SUM(cs.`project_score`) AS scoreSum,IFNULL(ca.`marks`,0) awardedMarks, 			(SUM(cs.`project_score`)+IFNULL(ca.`marks`,0)) AS totalPoint		FROM ct_score cs 			LEFT JOIN ct_project cp ON cs.`project_id`=cp.`project_id` 			LEFT JOIN aq_user au ON cs.`user_id`=au.`USER_ID` 			LEFT JOIN vw_xj_e_class vc ON cs.`class_id`=vc.`classid` 			LEFT JOIN `ct_awardedmarks` ca ON ca.`class_id`=cs.`class_id` AND ca.`user_id`=cs.`user_id`			,(SELECT @prev_value := NULL) f,(SELECT @rank_count := 0)  m		WHERE cp.`participant`='Personal' 		GROUP BY cs.`user_id`) t ORDER BY totalPoint DESC;