MySQL中, 如何查询某一天, 某一月, 某一年的数据

转自：https://www.cnblogs.com/azhqiang/p/6702950.html

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天(包括昨天和今天的数据)

select * from 表名 where to_days( now( ) ) - to_days( 时间字段名) <= 1

昨天(只包括昨天)

select * from 表名 where datediff(字段,now())=-1; -- 同理，查询前天的就是-2

近7天

select * from 表名 where date_sub(curdate(), interval 7 day) <= date(时间字段名)

近30天

select * from 表名 where date_sub(curdate(), interval 30 day) <= date(时间字段名)

本月

select * from 表名 where date_format( 时间字段名, '%y%m' ) = date_format( curdate( ) , '%y%m' )

上一月

select * from 表名 where period_diff( date_format( now( ) , '%y%m' ) , date_format( 时间字段名, '%y%m' ) ) =1

查询本季度数据

select * from `ht_invoice_information` where quarter(create_date)=quarter(now());

查询上季度数据

select * from `ht_invoice_information` where quarter(create_date)=quarter(date_sub(now(),interval 1 quarter));

查询本年数据

select * from `ht_invoice_information` where year(create_date)=year(now());

查询上年数据

select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据

select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now());

查询上周的数据

select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now())-1;

查询上个月的数据

 

　select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(date_sub(curdate(), interval 1 month),'%y-%m')

select * from user where date_format(pudate,'%y%m') = date_format(curdate(),'%y%m') ; 

select * from user where weekofyear(from_unixtime(pudate,'%y-%m-%d')) = weekofyear(now()) 

select * from user where month(from_unixtime(pudate,'%y-%m-%d')) = month(now()) 

select * from user where year(from_unixtime(pudate,'%y-%m-%d')) = year(now()) and month(from_unixtime(pudate,'%y-%m-%d')) = month(now()) 

select * from user where pudate between  上月最后一天  and 下月第一天 

查询当前月份的数据 

select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(now(),'%y-%m')

查询距离当前现在6个月的数据

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();