欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  IT编程

PHP+MySQL实现的简单投票系统实例

程序员文章站 2024-04-01 18:46:28
本文实例讲述了php+mysql实现的简单投票系统。分享给大家供大家参考,具体如下:

本文实例讲述了php+mysql实现的简单投票系统。分享给大家供大家参考,具体如下:

<html>
<head><title>手机系统调查问卷</title>
<style type="text/css">
<!--
span{
  width:600px;
  height:100px;
  background-color:write;
  postion:relative;
  border:1px #cccccc solid;
}
div{
  width:60px;
  height:1px;
  background-color:blue;
  postion:absolute;
  bottom:0;
}
-->
</style>
</head>
<body>
你现在使用的手机是什么系统?
<form id="form1" method="post" action="count.php">
<input type="radio" name="phone" value="1"> android安卓
<input type="radio" name="phone" value="2"> symbian塞班
<br>
<input type="radio" name="phone" value="3"> iphone苹果
<input type="radio" name="phone" value="4"> google谷歌
<br>
<input type="radio" name="phone" value="5"> winphone微软
<input type="radio" name="phone" value="6"> 其它
<br>
<input type="submit" value="提交">
</form>
<span>
当前票数:<br>
<?php
include 'connect.php';
$sql="select answer from countone";
$rs=mysql_query($sql);
$total=mysql_num_rows($rs);
$sql="select * from countone where answer=1";
$rs=mysql_query($sql);
$android=mysql_num_rows($rs);
$sql="select * from countone where answer=2";
$rs=mysql_query($sql);
$symbian=mysql_num_rows($rs);
$sql="select * from countone where answer=3";
$rs=mysql_query($sql);
$iphone=mysql_num_rows($rs);
$sql="select * from countone where answer=4";
$rs=mysql_query($sql);
$google=mysql_num_rows($rs);
$sql="select * from countone where answer=5";
$rs=mysql_query($sql);
$winphone=mysql_num_rows($rs);
$sql="select * from countone where answer=6";
$rs=mysql_query($sql);
$other=mysql_num_rows($rs);
?>
<table border="0">
<th>android</th><th>symbian</th><th>iphone</th><th>google</th><th>winphone</th><th>other</th>
<tr>
<td><?php echo $android ?>票</td>
<td><?php echo $symbian ?>票</td>
<td><?php echo $iphone ?>票</td>
<td><?php echo $google ?>票</td>
<td><?php echo $winphone ?>票</td>
<td><?php echo $other ?>票</td>
</tr>
<tr>
<td><?php for ($i=1;$i<=$android/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td>
<td><?php for ($i=1;$i<=$symbian/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td>
<td><?php for ($i=1;$i<=$iphone/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td>
<td><?php for ($i=1;$i<=$google/$total+1;$i=$i+0.1){  echo "<div></div>"; } ?></td>
<td><?php for ($i=1;$i<=$winphone/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td>
<td><?php for ($i=1;$i<=$other/$total+1;$i=$i+0.1){ echo "<div></div>"; } ?></td>
</tr>
</table>
</span>
</body>
</html>

写的有点啰嗦,有点笨但很实用

<?php
include 'connect.php';
$name=$_post['phone'];
$sql="insert into countone values(null,$name,now(),null)";
mysql_query($sql);
?>
<script type="text/javascript">
 alert ("投票成功!");
 location="question.php";
</script>

链接mysql:

<?php
mysql_connect("localhost","root","");
mysql_select_db("vote");
mysql_query("set names utf8");
?>

更多关于php相关内容感兴趣的读者可查看本站专题:《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总

希望本文所述对大家php程序设计有所帮助。