汉诺塔递归nefu 564

#include <bits/stdc++.h>

using namespace std;
void hannota(int n,char a,char b,char c)
{
    if(n==1)
        printf("number..%d..form..%c..to..%c\n",n,a,c);
    else
    {
        hannota(n-1,a,c,b);
        printf("number..%d..form..%c..to..%c\n",n,a,c);
        hannota(n-1,b,a,c);
    }
}



int main()
{
    int n;
    char a='A',b='B',c='C';
    while(cin>>n)
    {
        hannota(n,a,b,c);
    }
    return 0;
}