欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页

SQLSERVER索引的维护

程序员文章站 2024-03-20 09:37:28
...

sqlserver提升效率的有效方法是建立索引,但索引在增删改的过程中会产生碎片,碎片会影响性能,所以需要清理已达到提升性能的目的。

可以使用dm_db_index_physical_stats查询碎片状态,如果超过30%需要重新建立索引,如果在5%~30%之间,需要重新组织。

具体可以参考以下SQL:

 --取得需要重新组织的索引信息
SELECT
s.schema_id,
base.object_id,
base.index_id, 
base.avg_fragmentation_in_percent, s.name AS schemaname, o.name AS tablename, i.name AS indexname FROM sys.dm_db_index_physical_stats (DB_ID(N'MvcBlog'), NULL, NULL , NULL, NULL) AS base INNER JOIN sys.objects AS o ON o.object_id = base.object_id INNER JOIN sys.schemas AS s ON s.schema_id = o.schema_id INNER JOIN sys.indexes AS i ON i.object_id = base.object_id AND i.index_id = base.index_id WHERE base.avg_fragmentation_in_percent between 5 and 30 --5%~30% AND base.index_id > 0; --循环上面取得结果,执行重新组织索引语句 ALTER INDEX [IndexName] ON [SchemaName].[TableName] REORGANIZE; --取得需要重新组织的索引信息 SELECT s.schema_id, base.object_id,
base.index_id,
base.avg_fragmentation_in_percent, s.name AS schemaname, o.name AS tablename, i.name AS indexname FROM sys.dm_db_index_physical_stats (DB_ID(N'MvcBlog'), NULL, NULL , NULL, NULL) AS base INNER JOIN sys.objects AS o ON o.object_id = base.object_id INNER JOIN sys.schemas AS s ON s.schema_id = o.schema_id INNER JOIN sys.indexes AS i ON i.object_id = base.object_id AND i.index_id = base.index_id WHERE base.avg_fragmentation_in_percent > 30 --30%以上 AND base.index_id > 0; --循环上面取得结果,执行重新建立索引语句 ALTER INDEX [IndexName] ON [SchemaName].[TableName] REBUILD;

 

--重新建立表JNJA0001REC的所有索引	
ALTER INDEX ALL ON JNJA0001REC REBUILD;