模拟
没怎么看题。。直接deque模拟水过了。。
但是后来回过头看了下题意。。如果再次拿到正面朝上的牌,应该是废操作。。可能是数据太水了。。。
#include <bits/stdc++.h>
#define INF 0x3f3f3f3f
#define full(a, b) memset(a, b, sizeof a)
using namespace std;
typedef long long ll;
inline int lowbit(int x){ return x & (-x); }
inline int read(){
int X = 0, w = 0; char ch = 0;
while(!isdigit(ch)) { w |= ch == '-'; ch = getchar(); }
while(isdigit(ch)) X = (X << 3) + (X << 1) + (ch ^ 48), ch = getchar();
return w ? -X : X;
}
inline int gcd(int a, int b){ return a % b ? gcd(b, a % b) : b; }
inline int lcm(int a, int b){ return a / gcd(a, b) * b; }
template<typename T>
inline T max(T x, T y, T z){ return max(max(x, y), z); }
template<typename T>
inline T min(T x, T y, T z){ return min(min(x, y), z); }
template<typename A, typename B, typename C>
inline A fpow(A x, B p, C lyd){
A ans = 1;
for(; p; p >>= 1, x = 1LL * x * x % lyd)if(p & 1)ans = 1LL * x * ans % lyd;
return ans;
}
deque<char> q[13];
map<char, int> m;
int vis[14];
char s[] = {'A', '2', '3', '4', '5', '6', '7', '8', '9', '0', 'J', 'Q', 'K'};
void init(){
m['A'] = 0, m['2'] = 1, m['3'] = 2, m['4'] = 3;
m['5'] = 4, m['6'] = 5, m['7'] = 6, m['8'] = 7;
m['9'] = 8, m['0'] = 9, m['J'] = 10, m['Q'] = 11, m['K'] = 12;
}
int main(){
int ans = 0;
init();
for(int i = 0; i < 13; i ++){
for(int j = 0; j < 4; j ++){
char ch; cin >> ch;
q[i].push_back(ch);
}
}
int tmp = 0, cur = m[q[12].front()];
q[12].pop_front();
while(tmp < 4){
if(cur == 12){
tmp ++, cur = m[q[12].front()], q[12].pop_front();
continue;
}
vis[cur] ++;
if(vis[cur] == 4) ans ++;
int temp = cur;
cur = m[q[temp].back()], q[temp].pop_back(), q[temp].push_front(s[temp]);
}
printf("%d\n", ans);
return 0;
}