C++面向对象程序设计大作业:魔兽世界(三):开战
问题描述
问题来自于北京大学郭炜老师的C++慕课的大作业
魔兽世界的西面是红魔军的司令部,东面是蓝魔军的司令部。两个司令部之间是依次排列的若干城市,城市从西向东依次编号为1,2,3 … N ( N <= 20)。红魔军的司令部算作编号为0的城市,蓝魔军的司令部算作编号为N+1的城市。司令部有生命元,用于制造武士。
两军的司令部都会制造武士。武士一共有dragon 、ninja、iceman、lion、wolf 五种。每种武士都有编号、生命值、攻击力这三种属性。
双方的武士编号都是从1开始计算。红方制造出来的第n 个武士,编号就是n。同样,蓝方制造出来的第n 个武士,编号也是n。
武士在刚降生的时候有一个初始的生命值,生命值在战斗中会发生变化,如果生命值减少到0(生命值变为负数时应当做变为0处理),则武士死亡(消失)。
武士可以拥有武器。武器有三种,sword, bomb,和arrow,编号分别为0,1,2。
sword的攻击力是使用者当前攻击力的20%(去尾取整)。
bomb的攻击力是使用者当前攻击力的40%(去尾取整),但是也会导致使用者受到攻击,对使用者的攻击力是对敌人取整后的攻击力的1/2(去尾取整)。Bomb一旦使用就没了。
arrow的攻击力是使用者当前攻击力的30%(去尾取整)。一个arrow用两次就没了。
武士降生后就朝对方司令部走,在经过的城市如果遇到敌人(同一时刻每个城市最多只可能有1个蓝武士和一个红武士),就会发生战斗。战斗的规则是:
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在奇数编号城市,红武士先发起攻击
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在偶数编号城市,蓝武士先发起攻击
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战斗开始前,双方先对自己的武器排好使用顺序,然后再一件一件地按顺序使用。编号小的武器,排在前面。若有多支arrow,用过的排在前面。排好序后,攻击者按此排序依次对敌人一件一件地使用武器。如果一种武器有多件,那就都要用上。每使用一件武器,被攻击者生命值要减去武器攻击力。如果任何一方生命值减为0或小于0即为死去。有一方死去,则战斗结束。
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双方轮流使用武器,甲用过一件,就轮到乙用。某一方把自己所有的武器都用过一轮后,就从头开始再用一轮。如果某一方没有武器了,那就挨打直到死去或敌人武器用完。武器排序只在战斗前进行,战斗中不会重新排序。
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如果双方武器都用完且都还活着,则战斗以平局结束。如果双方都死了,也算平局。
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有可能由于武士自身攻击力太低,而导致武器攻击力为0。攻击力为0的武器也要使用。如果战斗中双方的生命值和武器的状态都不再发生变化,则战斗结束,算平局。
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战斗的胜方获得对方手里的武器。武士手里武器总数不超过10件。缴获武器时,按照武器种类编号从小到大缴获。如果有多件arrow,优先缴获没用过的。
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如果战斗开始前双方都没有武器,则战斗视为平局。如果先攻击方没有武器,则由后攻击方攻击。
不同的武士有不同的特点。
编号为n的dragon降生时即获得编号为n%3 的武器。dragon在战斗结束后,如果还没有战死,就会欢呼。
编号为n的ninjia降生时即获得编号为n%3 和(n+1)%3的武器。ninja 使用bomb不会让自己受伤。
编号为n的iceman降生时即获得编号为n%3 的武器。iceman每前进一步,生命值减少10%(减少的量要去尾取整)。
编号为n的lion降生时即获得编号为n%3 的武器。lion 有“忠诚度”这个属性,其初始值等于它降生之后其司令部剩余生命元的数目。每前进一步忠诚度就降低K。忠诚度降至0或0以下,则该lion逃离战场,永远消失。但是已经到达敌人司令部的lion不会逃跑。lion在己方司令部可能逃跑。
wolf降生时没有武器,但是在战斗开始前会抢到敌人编号最小的那种武器。如果敌人有多件这样的武器,则全部抢来。Wolf手里武器也不能超过10件。如果敌人arrow太多没法都抢来,那就先抢没用过的。如果敌人也是wolf,则不抢武器。
以下是不同时间会发生的不同事件:
在每个整点,即每个小时的第0分, 双方的司令部中各有一个武士降生。
红方司令部按照iceman、lion、wolf、ninja、dragon 的顺序制造武士。
蓝方司令部按照lion、dragon、ninja、iceman、wolf 的顺序制造武士。
制造武士需要生命元。
制造一个初始生命值为m 的武士,司令部中的生命元就要减少m 个。
如果司令部中的生命元不足以制造某本该造的武士,那就从此停止制造武士。
在每个小时的第5分,该逃跑的lion就在这一时刻逃跑了。
在每个小时的第10分:所有的武士朝敌人司令部方向前进一步。即从己方司令部走到相邻城市,或从一个城市走到下一个城市。或从和敌军司令部相邻的城市到达敌军司令部。
在每个小时的第35分:在有wolf及其敌人的城市,wolf要抢夺对方的武器。
在每个小时的第40分:在有两个武士的城市,会发生战斗。
在每个小时的第50分,司令部报告它拥有的生命元数量。
在每个小时的第55分,每个武士报告其拥有的武器情况。
武士到达对方司令部后就算完成任务了,从此就呆在那里无所事事。
任何一方的司令部里若是出现了敌人,则认为该司令部已被敌人占领。
任何一方的司令部被敌人占领,则战争结束。战争结束之后就不会发生任何事情了。
给定一个时间,要求你将从0点0分开始到此时间为止的所有事件按顺序输出。事件及其对应的输出样例如下:
- 武士降生
输出样例:000:00 blue dragon 1 born
表示在0点0分,编号为1的蓝魔dragon武士降生
如果造出的是lion,那么还要多输出一行,例:
000:00 blue lion 1 born
Its loyalty is 24
表示该lion降生时的忠诚度是24
- lion逃跑
输出样例:000:05 blue lion 1 ran away
表示在0点5分,编号为1的蓝魔lion武士逃走
- 武士前进到某一城市
输出样例:
000:10 red iceman 1 marched to city 1 with 20 elements and force 30
表示在0点10分,红魔1号武士iceman前进到1号城市,此时他生命值为20,攻击力为30
对于iceman,输出的生命值应该是变化后的数值
- wolf抢敌人的武器
000:35 blue wolf 2 took 3 bomb from red dragon 2 in city 4
表示在0点35分,4号城市中,红魔1号武士wolf 抢走蓝魔2号武士dragon 3个bomb。为简单起见,武器不写复数形式
- 报告战斗情况
战斗只有3种可能的输出结果:
000:40 red iceman 1 killed blue lion 12 in city 2 remaining 20 elements
表示在0点40分,1号城市中,红魔1号武士iceman 杀死蓝魔12号武士lion后,剩下生命值20
000:40 both red iceman 1 and blue lion 12 died in city 2
注意,把红武士写前面
000:40 both red iceman 1 and blue lion 12 were alive in city 2
注意,把红武士写前面
- 武士欢呼
输出样例:003:40 blue dragon 2 yelled in city 4
- 武士抵达敌军司令部
输出样例:001:10 red iceman 1 reached blue headquarter with 20 elements and force 30
(此时他生命值为20,攻击力为30)对于iceman,输出的生命值和攻击力应该是变化后的数值
- 司令部被占领
输出样例:003:10 blue headquarter was taken
9)司令部报告生命元数量
000:50 100 elements in red headquarter
000:50 120 elements in blue headquarter
表示在0点50分,红方司令部有100个生命元,蓝方有120个
10)武士报告情况
000:55 blue wolf 2 has 2 sword 3 bomb 0 arrow and 7 elements
为简单起见,武器都不写复数形式。elements一律写复数,哪怕只有1个
交代武器情况时,次序依次是:sword,bomb, arrow。
输出事件时:
首先按时间顺序输出;
同一时间发生的事件,按发生地点从西向东依次输出. 武士前进的事件, 算是发生在目的地。
在一次战斗中有可能发生上面的 5 至 6 号事件。这些事件都算同时发生,其时间就是战斗开始时间。一次战斗中的这些事件,序号小的应该先输出。
两个武士同时抵达同一城市,则先输出红武士的前进事件,后输出蓝武士的。
对于同一城市,同一时间发生的事情,先输出红方的,后输出蓝方的。
显然,8号事件发生之前的一瞬间一定发生了7号事件。输出时,这两件事算同一时间发生,但是应先输出7号事件
虽然任何一方的司令部被占领之后,就不会有任何事情发生了。但和司令部被占领同时发生的事件,全都要输出。
输入第一行是t,代表测试数据组数
每组样例共三行。
第一行,4个整数 M,N,K, T。其含义为:
每个司令部一开始都有M个生命元( 1 <= M <= 100000)
两个司令部之间一共有N个城市( 1 <= N <= 20 )
lion每前进一步,忠诚度就降低K。(0<=K<=100)
要求输出从0时0分开始,到时间T为止(包括T) 的所有事件。T以分钟为单位,0 <= T <= 6000
第二行:五个整数,依次是 dragon 、ninja、iceman、lion、wolf 的初始生命值。它们都大于0小于等于200
第三行:五个整数,依次是 dragon 、ninja、iceman、lion、wolf 的攻击力。它们都大于0小于等于200输出对每组数据,先输出一行:
Case n:
如对第一组数据就输出 Case 1:
然后按恰当的顺序和格式输出到时间T为止发生的所有事件。每个事件都以事件发生的时间开头,时间格式是“时: 分”,“时”有三位,“分”有两位。样例输入
1
20 1 10 400
20 20 30 10 20
5 5 5 5 5
样例输出
Case 1:
000:00 blue lion 1 born
Its loyalty is 10
000:10 blue lion 1 marched to city 1 with 10 elements and force 5
000:50 20 elements in red headquarter
000:50 10 elements in blue headquarter
000:55 blue lion 1 has 0 sword 1 bomb 0 arrow and 10 elements
001:05 blue lion 1 ran away
001:50 20 elements in red headquarter
001:50 10 elements in blue headquarter
002:50 20 elements in red headquarter
002:50 10 elements in blue headquarter
003:50 20 elements in red headquarter
003:50 10 elements in blue headquarter
004:50 20 elements in red headquarter
004:50 10 elements in blue headquarter
005:50 20 elements in red headquarter
005:50 10 elements in blue headquarter
提示
请注意浮点数精度误差问题。OJ上的编译器编译出来的可执行程序,在这方面和你电脑上执行的程序很可能会不一致。5 * 0.3 的结果,有的机器上可能是 15.00000001,去尾取整得到15,有的机器上可能是14.9999999,去尾取整后就变成14。因此,本题不要写 5 * 0.3,要写 5 * 3 / 10。
来源
Guo Wei
问题分析
这是我2018年上慕课学习的时候课程最后的大作业,好像占了总成绩的5分还是10分来着。这个大作业的庞大和复杂程度是毋庸置疑的,好像分成四个阶段,以上的问题是第三阶段,此外还有个“终极版”。
当然这个问题也是显然超出我能力范围的¯⌓¯。我记得前两个阶段在课程学习过程中,我是自己写出来的,但这个第三阶段和第二阶段的跨度也太大了。书本上老师对此大作业的描述是“学生普遍反映,这样的程序确实需要面向对象的程序设计方法来编写,否则不但在程序设计时思路难以理清,要修改时更是会非常麻烦。”这话一点不假,然而我觉得即使是用了面向对象,这问题一样难以理清。。Σ_(꒪ཀ꒪」∠)
我当时也上网找了人家写好的,但是人家写的,和老师给出的第二阶段的“参考程序”是无法衔接的,我就想把两者结合起来,以第二阶段老师的“参考程序”为基础,结合网上看来的别人的思路和逻辑,然后写了出来,好不容易好不容易编译通过,但是程序运行不起来。拿IDE直接调试,遇到变量的复杂繁多,费头脑的指针变量,盘根交错的函数调用关系……,发现根本没法调试。为此,我还到处发帖、百度询问:“怎样调试复杂大型程序?”͡[๏̯͡๏] 然而并没有找到什么对我有用的答案。。最后只能放弃。
2019,2020年,我都把这个大作业翻出来再努力过,前段时间看到网上有人说打log调试程序,我啪的一下就站起来了,很快啊!我以前怎么没这样调试程序?马上就用小黄鸭调试法+printf大法开始调试,一发不可收拾,发现特别管用,每次调试,每天调试都有进步,根本停不下来。经过好久好久,终于干成功了。此时程序已经和当初写好的相差很大很大了。搞完之后。。终于舒服了。。
写完总结一下,有这么几个值得注意的问题:
- 我参考了这位老哥写的程序的逻辑别人写的,但是经过仔细研究,他这个程序逻辑和问题描述不符合(在战斗部分的武器使用和战斗结尾的武器获取部分),拿示例的基础测试数据是对的,但是拿其他测试数据可能不对。我自己想破了头脑改了自己觉得符合题意的逻辑,用老师给的11组测试数据,是没问题的,但有没有隐藏错误就不知道了。
- 我想在老师给的第二阶段参考程序的基础上写第三阶段,比较死板,可能不是好方法。(但不参考我也是一点头绪都没有的。。)
- 调试我程序的N多N多错误中,大概六成是指针应用错误(内存泄漏+空悬指针),写的复杂了,指针的错误真的是防不胜防。教训就是以后 使用、释放指针前一定要判断是否有意义,不用指针的时候一定要置NULL 。另外这也凸显智能指针(auto_ptr/shared_ptr)的优势,不过这些没咋学我还不会用。。;另外三成错误是逻辑本身错误;另外一成是低级语法错误(括号对不上,==写成=)之类。
- 我看着那位老哥写的程序也被带跑偏了,他的类成员全部写成public,后面全是直接的指针一级一级访问,我跟着写,也是这样。。最后程序完成后我想改回来,想把该封装的封装起来,才发现,,,太麻烦了!!我把武器类、武士类改了改,其他的类就放弃修改了。。
- 题目要求“同一时间发生的事件,按发生地点从西向东依次输出. 武士前进的事件, 算是发生在目的地;两个武士同时抵达同一城市,则先输出红武士的前进事件,后输出蓝武士的。”,我的程序在每小时第10分钟武士前进到某一城市的情况的输出顺序和该要求不符。 我是先把红军武士前进情况全输出来,再把蓝军武士前进情况输出来。因为我没想得出怎么改才能满足这个要求。。。除此之外,其他输出都正确。
另外,11组测试数据和结果太长了,我在这上不挂了。。。。找郭炜老师《C++面向对象程序设计》慕课的配套资料里应该有。
代码
在windows环境下用Code::Blocks编写编译的。
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
const int WARRIOR_NUM = 5;//五种武士
const int WEAPON_NUM = 3;//三种武器
const int WEAPON_MAX = 10;//一个武士最多10把武器
enum {DRAGON, NINJA, ICEMAN, LION, WOLF};
enum {SWORD, BOMB, ARROW};
using namespace std;
class Headquarter;
class Dragon;
class Ninja;
class Iceman;
class Lion;
class Wolf;
class Warrior;
class City;
class Weapon
{
protected:
int WeaponKind;
int WeaponForce;
static char *WeaponName[WEAPON_NUM];
Warrior *pWarrior;//该武器属于哪个武士
bool Used; //为arrow准备的,标志arrow是否用过。
Weapon(int kind, Warrior *p);
friend int compareWeapon (const void *p, const void *q);//qsort函数的比较函数,用过的arrow排前面
friend int compareWeapon2 (const void *p, const void *q);//qsort函数的比较函数,没用过的arrow排前面
friend class Warrior;
friend class Dragon;
friend class Ninja;
friend class Iceman;
friend class Lion;
friend class Wolf;
};
class Warrior
{
protected:
Headquarter *pHeadquarter; //武士属于红还是蓝司令部
City *pCity;//武士目前在哪个City
int OrderInMaking;//武士的种类
int OrderInTotal;//武士是红/蓝司令部制造的第几个武士
Weapon *Weaponptr[WEAPON_MAX];//武士拥有的武器数组
int SumWeap;//武器总数
int UsedArrow;//用过的Arrow的数量
int NumOfWeapon[WEAPON_NUM];//各种武器有多少把
int Life;
public:
friend class Weapon;
friend class Headquarter;
friend class City;
friend class Dragon;
friend class Ninja;
friend class Iceman;
friend class Lion;
friend class Wolf;
friend void RedWarriorMove(City * leftCity, City *rightCity, int Time);
friend void BlueWarriorMove(City *rightCity, City * leftCity, int Time);
static char *WarriorName[WARRIOR_NUM];//存武士名字的全局字符串数组
static int InitLifeValue[WARRIOR_NUM];//存武士初始生命值的全局数组
static int AttackForce[WARRIOR_NUM];//存武士攻击力的全局数组
Warrior(Headquarter *_p, int _oim, int _oit): pHeadquarter(_p),
OrderInMaking(_oim),
OrderInTotal(_oit),
SumWeap(0),
UsedArrow(0),
Life(InitLifeValue[OrderInMaking])
{
for (int i = 0; i < WEAPON_NUM; ++i)
NumOfWeapon[i] = 0;
for (int i = 0; i < WEAPON_MAX; ++i)
Weaponptr[i] = NULL;
}
virtual ~Warrior()
{
for (int i = 0; i < SumWeap; i++)
if (Weaponptr[i])
delete Weaponptr[i];
}
virtual void PrintResult(int Time);//武士降生时报告情况
virtual void IcemanMove() {}
virtual bool LionEscape(int Time)
{
return 0;
}
virtual void LionMove() {}
virtual void Rob(Warrior *enemy, int Time) {}
void CaptureWeapon(Warrior *another);//击败对方武士后抢夺武器
void ArrangeWeapon();//战斗之前把武器排好序
void WarriorAnnounce(int Time);//每小时55钟的时候报告情况
void OneTimeAttack(Warrior *another, int OrderInWeaponptr);//攻击对方
int WarriorKind() {return OrderInMaking;}
int WarriorOrderInTotal() {return OrderInTotal;}
};
class City
{
public:
int Cityname;
Warrior *redwarrior;
Warrior *bluewarrior;
bool ishead;//该City是否为司令部
friend void RedWarriorMove(City * leftCity, City *rightCity, int Time);
friend void BlueWarriorMove(City *rightCity, City * leftCity, int Time);
bool attackResult(int Time, Headquarter * Red, Headquarter * Blue);//每小时的40分报告战斗情况
void Battling(int Time, Headquarter * Red, Headquarter * Blue);//City发生战斗
void RedInit(Headquarter *p);//红司令部成为最左的City
void BlueInit(Headquarter *p);//蓝司令部成为最右的City
};
class Headquarter
{
public:
friend class Warrior;
friend class City;
int Color;
int TotalLifeValue;//总共有多少生命元
int CurOrderInMaking;//接下来准备产生哪种武士
int TotalWarriorNum;//总共有多少活着的武士
int NumOfWarrior[WARRIOR_NUM];//每种武士有多少个
Warrior *Wptr[1000];//武士数组
bool Stop;//该司令部是否有足够生命元继续生产武士
static bool MainFlag;//全局量,标志是否被占领
static int MakingOrder[2][WARRIOR_NUM];//存放武士制造顺序的数组
Headquarter(bool _color, int _lifevalue): Color(_color),
TotalLifeValue(_lifevalue),
CurOrderInMaking(0),
TotalWarriorNum(0),
Stop(false)
{
for (int i = 0; i < WARRIOR_NUM; i++)
NumOfWarrior[i] = 0;
for (int i = 0; i < 1000; ++i)
Wptr[i] = NULL;
}
~Headquarter()
{
for (int i = 0; i < TotalWarriorNum; i++)
if (Wptr[i])
delete Wptr[i];
}
void Produce(int Time);//武士降生
void GetColor(char *HeadquarterName);//get “red” or “blue”
void HeadAnnounce(int Time);//每小时的50分司令部报告生命元数量
int GetTotalLifeValue() { return TotalLifeValue; }
void DestroyWarrior(int number) {
Wptr[number] = NULL;
}
};
class Dragon: public Warrior
{
friend class Headquarter;
friend class City;
friend class Ninja;
friend class Iceman;
friend class Lion;
friend class Wolf;
public:
Dragon(Headquarter *_p, int _oim, int _oit): Warrior(_p, _oim, _oit)
{
int kind = OrderInTotal % WEAPON_NUM;
Weaponptr[SumWeap] = new Weapon(kind, this);
NumOfWeapon[kind]++;
SumWeap++;
}
void PrintResult(int Time)
{
Warrior::PrintResult(Time);
}
};
class Ninja: public Warrior
{
friend class Headquarter;
friend class City;
friend class Dragon;
friend class Iceman;
friend class Lion;
friend class Wolf;
public:
Ninja(Headquarter *_p, int _oim, int _oit): Warrior(_p, _oim, _oit)
{
int kind = OrderInTotal % WEAPON_NUM;
Weaponptr[SumWeap] = new Weapon(kind,this);
NumOfWeapon[kind]++;
SumWeap++;
kind = (OrderInTotal + 1) % WEAPON_NUM;
Weaponptr[SumWeap] = new Weapon(kind,this);
NumOfWeapon[kind]++;
SumWeap++;
}
void PrintResult(int Time)
{
Warrior::PrintResult(Time);
}
};
class Iceman: public Warrior
{
friend class Headquarter;
friend class City;
friend class Dragon;
friend class Lion;
friend class Wolf;
friend class Ninja;
public:
Iceman(Headquarter *_p, int _oim, int _oit): Warrior(_p, _oim, _oit)
{
int kind = OrderInTotal % WEAPON_NUM;
Weaponptr[SumWeap] = new Weapon(kind,this);
NumOfWeapon[kind]++;
SumWeap++;
}
void PrintResult(int Time)
{
Warrior::PrintResult(Time);
}
void IcemanMove()
{
Life -= Life / 10;
}
};
class Lion: public Warrior
{
friend class Headquarter;
friend class City;
friend class Dragon;
friend class Iceman;
friend class Wolf;
friend class Ninja;
protected:
int Loyalty;
public:
static int LoyaltyDecrease;//每前进一步忠诚度降低值
void GetLoyalty()
{
Loyalty = pHeadquarter->GetTotalLifeValue();
}
Lion(Headquarter *_p, int _oim, int _oit): Warrior(_p, _oim, _oit)
{
GetLoyalty();
int kind = OrderInTotal % WEAPON_NUM;
Weaponptr[SumWeap] = new Weapon(kind,this);
NumOfWeapon[kind]++;
SumWeap++;
}
void PrintResult(int Time)
{
Warrior::PrintResult(Time);
printf("It's loyalty is %d\n", Loyalty);
}
bool LionEscape(int Time) {
if (Loyalty>0) return 0;
char HeadquarterName[20];
pHeadquarter->GetColor(HeadquarterName);
printf("%.3d:05 %s lion %d ran away\n", Time, HeadquarterName, OrderInTotal);
return 1;
} //judge whether the lion escapes
void LionMove() {
Loyalty-=LoyaltyDecrease;
}
};
class Wolf: public Warrior
{
friend class Headquarter;
friend class City;
friend class Dragon;
friend class Iceman;
friend class Lion;
friend class Ninja;
public:
Wolf(Headquarter *_p, int _oim, int _oit): Warrior(_p, _oim, _oit) {}
void PrintResult(int Time)
{
Warrior::PrintResult(Time);
}
void Rob(Warrior *enemy, int Time);
};
int compareWeapon (const void *p, const void *q) //usedarrow排前面
{
const Weapon ** p1 = (const Weapon **)p;
const Weapon ** q1 = (const Weapon **)q;
if ((*p1)->WeaponKind < (*q1)->WeaponKind) return -1;
else if ((*p1)->WeaponKind == ARROW && (*q1)->WeaponKind == ARROW) {
if ((*p1)->Used == (*q1)->Used) return 0;
else if ((*p1)->Used > (*q1)->Used) return -1;
else return 1;
}
else if ((*p1)->WeaponKind == (*q1)->WeaponKind) return 0;
else return 1;
}
int compareWeapon2 (const void *p, const void *q) //usedarrow排后面
{
const Weapon ** p1 = (const Weapon **)p;
const Weapon ** q1 = (const Weapon **)q;
if ((*p1)->WeaponKind < (*q1)->WeaponKind) return -1;
else if ((*p1)->WeaponKind == ARROW && (*q1)->WeaponKind == ARROW) {
if ((*p1)->Used == (*q1)->Used) return 0;
else if ((*p1)->Used < (*q1)->Used) return -1;
else return 1;
}
else if ((*p1)->WeaponKind == (*q1)->WeaponKind) return 0;
else return 1;
}
void Wolf::Rob(Warrior *enemy, int Time)
{
if (enemy->OrderInMaking == WOLF) return;
if (SumWeap == 10 || enemy->SumWeap == 0) return;
int i_ = 0, used_change = 0;//used-change是抢的用过的arrow的数量
for (; i_ < WEAPON_NUM; ++i_)
if (enemy->NumOfWeapon[i_] > 0) break;
int robNum = min(enemy->NumOfWeapon[i_], WEAPON_MAX - SumWeap);
if (i_ == ARROW) {
if (enemy->NumOfWeapon[ARROW] - enemy->UsedArrow < robNum) {
used_change = robNum - (enemy->NumOfWeapon[ARROW] - enemy->UsedArrow);
enemy->UsedArrow -= used_change;
UsedArrow += used_change;
}
}
for (int i = 0; i < robNum; ++i)
Weaponptr[SumWeap+i] = new Weapon(i_,this);
if (i_ == ARROW) {
for (int i = 0; i < used_change; i++)
Weaponptr[SumWeap+i]->Used = true;
}
SumWeap += robNum;
NumOfWeapon[i_] += robNum;
if (i_ != ARROW) {
for (int i = 0, cnt = 0; i < enemy->SumWeap && cnt < robNum; ++i)
if (enemy->Weaponptr[i]->WeaponKind == i_) {
delete enemy->Weaponptr[i];
enemy->Weaponptr[i] = NULL;
++cnt;
}
}
else {
for (int i = 0, cnt = 0; i < enemy->SumWeap && cnt < (robNum - used_change); ++i)
if (enemy->Weaponptr[i]->WeaponKind == i_) {
if (!(enemy->Weaponptr[i]->Used)) {
delete enemy->Weaponptr[i];
enemy->Weaponptr[i] = NULL;
++cnt;
}
}
for (int i = 0, cnt = 0; i < enemy->SumWeap && cnt < used_change; ++i)
if (enemy->Weaponptr[i]->WeaponKind == i_) {
if (enemy->Weaponptr[i]->Used) {
delete enemy->Weaponptr[i];
enemy->Weaponptr[i] = NULL;
++cnt;
}
}
}
//抢完之后要给武器数组进行及时排好序:
Weapon *Weaponptr_tmp[WEAPON_MAX];
for (int i = 0; i < WEAPON_MAX; i++)
Weaponptr_tmp[i] = NULL;
for (int i = 0, k = 0; i < WEAPON_MAX; ++i)
if (enemy->Weaponptr[i]) {
Weaponptr_tmp[k] = enemy->Weaponptr[i];
k++;
}
for (int i = 0; i < WEAPON_MAX; ++i)
enemy->Weaponptr[i] = Weaponptr_tmp[i];
for (int i = 0; i < WEAPON_MAX; ++i)
Weaponptr_tmp[i] = NULL;
enemy->SumWeap -= robNum;
enemy->NumOfWeapon[i_] -= robNum;
if (enemy->SumWeap > 0) qsort(enemy->Weaponptr, enemy->SumWeap, sizeof(Weapon *), compareWeapon);
qsort(Weaponptr, SumWeap, sizeof(Weapon *), compareWeapon);
//000:35 blue wolf 2 took 3 bomb from red dragon 2 in city 4
char HeadquarterName1[20];
pHeadquarter->GetColor(HeadquarterName1);
char HeadquarterName2[20];
enemy->pHeadquarter->GetColor(HeadquarterName2);
printf("%.3d:35 %s wolf %d took %d %s from %s %s %d in city %d\n", Time, HeadquarterName1, OrderInTotal,
robNum, Weapon::WeaponName[i_], HeadquarterName2,
WarriorName[enemy->OrderInMaking], enemy->OrderInTotal,
pCity->Cityname);
}
Weapon::Weapon(int kind, Warrior *p): WeaponKind(kind), pWarrior(p), Used(false)
{
switch (kind) {
case SWORD: WeaponForce = p->AttackForce[pWarrior->OrderInMaking] / 5;
break;
case BOMB : WeaponForce = p->AttackForce[pWarrior->OrderInMaking] * 2 / 5;
break;
case ARROW: WeaponForce = p->AttackForce[pWarrior->OrderInMaking] * 3 / 10;
break;
}
}
void City::RedInit(Headquarter *p)
{
redwarrior = p->Wptr[p->TotalWarriorNum-1];
redwarrior->pCity = this;
}
void City::BlueInit(Headquarter *p)
{
bluewarrior = p->Wptr[p->TotalWarriorNum-1];
bluewarrior->pCity = this;
}
void Warrior::PrintResult(int Time)
{
char HeadquarterName[20];
pHeadquarter->GetColor(HeadquarterName);
printf("%.3d:00 %s %s %d born\n", Time, HeadquarterName, WarriorName[OrderInMaking], OrderInTotal);
}
void Headquarter::Produce(int Time)
{
if (Stop) return;
if (Warrior::InitLifeValue[MakingOrder[Color][CurOrderInMaking]] > TotalLifeValue) {
Stop = true;
return;
}
int Kind = MakingOrder[Color][CurOrderInMaking];
TotalLifeValue -= Warrior::InitLifeValue[Kind];
CurOrderInMaking = (CurOrderInMaking + 1) % WARRIOR_NUM;
switch (Kind) {
case DRAGON: Wptr[TotalWarriorNum] = new Dragon(this, Kind, TotalWarriorNum+1);
break;
case NINJA : Wptr[TotalWarriorNum] = new Ninja(this, Kind, TotalWarriorNum+1);
break;
case ICEMAN: Wptr[TotalWarriorNum] = new Iceman(this, Kind, TotalWarriorNum+1);
break;
case LION : Wptr[TotalWarriorNum] = new Lion(this, Kind, TotalWarriorNum+1);
break;
case WOLF : Wptr[TotalWarriorNum] = new Wolf(this, Kind, TotalWarriorNum+1);
break;
}
NumOfWarrior[Kind]++;
Wptr[TotalWarriorNum]->PrintResult(Time);
TotalWarriorNum++;
}
void Headquarter::GetColor(char *HeadquarterName)
{
if (Color == 0)
strcpy(HeadquarterName, "red");
else
strcpy(HeadquarterName, "blue");
}
void RedWarriorMove(City * leftCity, City *rightCity, int Time)//从左往右
{
if (leftCity->redwarrior) {
if (leftCity->redwarrior->OrderInMaking == ICEMAN) leftCity->redwarrior->IcemanMove();
if (leftCity->redwarrior->OrderInMaking == LION) leftCity->redwarrior->LionMove();
char HeadquarterName[20];
leftCity->redwarrior->pHeadquarter->GetColor(HeadquarterName);
if (!rightCity->ishead)
//000:10 red iceman 1 marched to city 1 with 20 elements and force 30
printf("%.3d:10 %s %s %d marched to city %d with %d elements and force %d\n", Time, HeadquarterName, Warrior::WarriorName[leftCity->redwarrior->OrderInMaking],
leftCity->redwarrior->OrderInTotal, rightCity->Cityname, leftCity->redwarrior->Life,
Warrior::AttackForce[leftCity->redwarrior->OrderInMaking]);
else if (rightCity->ishead) {
//001:10 red iceman 1 reached blue headquarter with 20 elements and force 30
printf("%.3d:10 %s %s %d reached blue headquarter with %d elements and force %d\n", Time, HeadquarterName, Warrior::WarriorName[leftCity->redwarrior->OrderInMaking],
leftCity->redwarrior->OrderInTotal, leftCity->redwarrior->Life,
Warrior::AttackForce[leftCity->redwarrior->OrderInMaking]);
printf("%.3d:10 blue headquarter was taken\n",Time);//004:10 blue headquarter was taken
Headquarter::MainFlag = 0;
}
rightCity->redwarrior = leftCity->redwarrior;
leftCity->redwarrior = NULL;
rightCity->redwarrior->pCity = rightCity;
}
}
void BlueWarriorMove(City *rightCity, City * leftCity, int Time)
{//从you往zuo
if (rightCity->bluewarrior) {
if (rightCity->bluewarrior->OrderInMaking == ICEMAN) rightCity->bluewarrior->IcemanMove();
if (rightCity->bluewarrior->OrderInMaking == LION) rightCity->bluewarrior->LionMove();
char HeadquarterName[20];
rightCity->bluewarrior->pHeadquarter->GetColor(HeadquarterName);
if (!leftCity->ishead)
//000:10 red iceman 1 marched to city 1 with 20 elements and force 30
printf("%.3d:10 %s %s %d marched to city %d with %d elements and force %d\n", Time, HeadquarterName, Warrior::WarriorName[rightCity->bluewarrior->OrderInMaking],
rightCity->bluewarrior->OrderInTotal, leftCity->Cityname, rightCity->bluewarrior->Life,
Warrior::AttackForce[rightCity->bluewarrior->OrderInMaking]);
else if (leftCity->ishead) {
//001:10 red iceman 1 reached blue headquarter with 20 elements and force 30
printf("%.3d:10 %s %s %d reached red headquarter with %d elements and force %d\n", Time, HeadquarterName, Warrior::WarriorName[rightCity->bluewarrior->OrderInMaking],
rightCity->bluewarrior->OrderInTotal, rightCity->bluewarrior->Life,
Warrior::AttackForce[rightCity->bluewarrior->OrderInMaking]);
printf("%.3d:10 red headquarter was taken\n",Time);//004:10 blue headquarter was taken
Headquarter::MainFlag = 0;
}
leftCity->bluewarrior = rightCity->bluewarrior;
rightCity->bluewarrior = NULL;
leftCity->bluewarrior->pCity = leftCity;
}
}
void Warrior::OneTimeAttack(Warrior *another, int OrderInWeaponptr)
{
int usingKind = Weaponptr[OrderInWeaponptr]->WeaponKind;
switch (usingKind) {
case SWORD: another->Life -= Weaponptr[OrderInWeaponptr]->WeaponForce;
break;
case BOMB : another->Life -= Weaponptr[OrderInWeaponptr]->WeaponForce;
if (OrderInMaking != NINJA) {
Life -= Weaponptr[OrderInWeaponptr]->WeaponForce / 2;
}
delete Weaponptr[OrderInWeaponptr];
Weaponptr[OrderInWeaponptr] = NULL;
NumOfWeapon[usingKind]--;
break;
case ARROW: another->Life -= Weaponptr[OrderInWeaponptr]->WeaponForce;
if (Weaponptr[OrderInWeaponptr]->Used) {
delete Weaponptr[OrderInWeaponptr];
Weaponptr[OrderInWeaponptr] = NULL;
NumOfWeapon[usingKind]--;
UsedArrow--;
}
else{
UsedArrow++;
Weaponptr[OrderInWeaponptr]->Used = true;
}
break;
}
}
void Warrior::ArrangeWeapon()
{
SumWeap = NumOfWeapon[0] + NumOfWeapon[1] + NumOfWeapon[2];
Weapon *Weaponptr_tmp[WEAPON_MAX];
for (int i = 0; i < WEAPON_MAX; i++)
Weaponptr_tmp[i] = NULL;
for (int i = 0, k = 0; i < WEAPON_MAX; ++i)
if (Weaponptr[i]) {
Weaponptr_tmp[k] = Weaponptr[i];
k++;
}
for (int i = 0; i < WEAPON_MAX; ++i)
Weaponptr[i] = Weaponptr_tmp[i];
for (int i = 0; i < WEAPON_MAX; ++i)
Weaponptr_tmp[i] = NULL;
if (SumWeap > 0) qsort(Weaponptr, SumWeap, sizeof(Weapon *), compareWeapon);
}
void Warrior::CaptureWeapon(Warrior *another)
{
if ((WEAPON_MAX - SumWeap) > 0 && another->SumWeap > 0) {//自己武器没满,且对方还有武器,才要拿
int add;
if ((WEAPON_MAX - SumWeap) >= another->SumWeap) {
add = another->SumWeap;
Weapon *Weaponptr_tmp[add];
for (int i = 0; i < add; i++) {
int kind = another->Weaponptr[i]->WeaponKind;
bool used = another->Weaponptr[i]->Used;
Weaponptr_tmp[i] = new Weapon(kind, this);
if (kind == ARROW && used)
Weaponptr_tmp[i]->Used = true;
}
for (int i = 0; i < add; i++)
Weaponptr[SumWeap+i] = Weaponptr_tmp[i];
SumWeap += add;
NumOfWeapon[SWORD] += another->NumOfWeapon[SWORD];
NumOfWeapon[BOMB] += another->NumOfWeapon[BOMB];
NumOfWeapon[ARROW] += another->NumOfWeapon[ARROW];
}
else {
qsort(another->Weaponptr, another->SumWeap, sizeof(Weapon *), compareWeapon2);//把another没用过的排在前面
add = WEAPON_MAX - SumWeap;
Weapon *Weaponptr_tmp[add];
for (int i = 0; i < add; ++i) {
int kind = another->Weaponptr[i]->WeaponKind;
bool used = another->Weaponptr[i]->Used;
Weaponptr_tmp[i] = new Weapon(kind, this);
if (kind == ARROW && used)
Weaponptr_tmp[i]->Used = true;
if (kind == SWORD) NumOfWeapon[SWORD]++;
if (kind == BOMB) NumOfWeapon[BOMB]++;
if (kind == ARROW) NumOfWeapon[ARROW]++;
}
for (int i = 0; i < add; i++)
Weaponptr[SumWeap+i] = Weaponptr_tmp[i];
SumWeap += add;
}
}
}
bool City::attackResult(int Time, Headquarter * Red, Headquarter * Blue)
{
if (redwarrior->Life <= 0 && bluewarrior->Life <= 0) {
//000:40 both red iceman 1 and blue lion 12 died in city 2
printf("%.3d:40 both red %s %d and blue %s %d died in city %d\n", Time, Warrior::WarriorName[redwarrior->OrderInMaking], redwarrior->OrderInTotal,
Warrior::WarriorName[bluewarrior->OrderInMaking], bluewarrior->OrderInTotal, Cityname);
Red->DestroyWarrior(redwarrior->OrderInTotal-1);
delete redwarrior;
redwarrior = NULL;
Blue->DestroyWarrior(bluewarrior->OrderInTotal-1);
delete bluewarrior;
bluewarrior = NULL;
return 1;
}
if (bluewarrior->Life <= 0) {
redwarrior->ArrangeWeapon(); bluewarrior->ArrangeWeapon();
redwarrior->CaptureWeapon(bluewarrior);
redwarrior->ArrangeWeapon();
//000:40 red iceman 1 killed blue lion 12 in city 2 remaining 20 elements
printf("%.3d:40 red %s %d killed blue %s %d in city %d remaining %d elements\n", Time, Warrior::WarriorName[redwarrior->OrderInMaking], redwarrior->OrderInTotal,
Warrior::WarriorName[bluewarrior->OrderInMaking], bluewarrior->OrderInTotal, Cityname,
redwarrior->Life);
Blue->DestroyWarrior(bluewarrior->OrderInTotal-1);
delete bluewarrior;
bluewarrior = NULL;
if (redwarrior->OrderInMaking == DRAGON)
//003:40 blue dragon 2 yelled in city 4
printf("%.3d:40 red dragon %d yelled in city %d\n", Time, redwarrior->OrderInTotal, Cityname);
return 1;
}
if (redwarrior->Life <= 0) {
redwarrior->ArrangeWeapon(); bluewarrior->ArrangeWeapon();
bluewarrior->CaptureWeapon(redwarrior);
bluewarrior->ArrangeWeapon();
//000:40 red iceman 1 killed blue lion 12 in city 2 remaining 20 elements
printf("%.3d:40 blue %s %d killed red %s %d in city %d remaining %d elements\n", Time, Warrior::WarriorName[bluewarrior->OrderInMaking], bluewarrior->OrderInTotal,
Warrior::WarriorName[redwarrior->OrderInMaking], redwarrior->OrderInTotal, Cityname,
bluewarrior->Life);
Red->DestroyWarrior(redwarrior->OrderInTotal-1);
delete redwarrior;
redwarrior = NULL;
if (bluewarrior->OrderInMaking == DRAGON)
//003:40 blue dragon 2 yelled in city 4
printf("%.3d:40 blue dragon %d yelled in city %d\n", Time, bluewarrior->OrderInTotal, Cityname);
return 1;
}
return 0;
}
void City::Battling(int Time, Headquarter * Red, Headquarter * Blue)
{
if (!(redwarrior && bluewarrior)) return;//形不成战斗
bool tempFlag = 0;//标志战斗状态是否不再发生变化,我这里认为如果双方生命值连续五轮不变,那就是平局
int redlife = redwarrior->Life, bluelife = bluewarrior->Life;
int i_red = 0, i_blue = 0;//使用的是武士拥有的武器数组中序号为i_red/i_blue的武器
if (Cityname % 2 ==1) {
if (redwarrior->SumWeap) {
if (i_red == redwarrior->SumWeap) i_red = 0;
if (redwarrior->Weaponptr[i_red]) {
redwarrior->OneTimeAttack(bluewarrior, i_red);
if (attackResult(Time, Red, Blue)) return;
i_red++;
}
else {
int i;
for (i = i_red; i < redwarrior->SumWeap; i++)
if (redwarrior->Weaponptr[i]) break;
if (i < redwarrior->SumWeap) {
i_red = i;
redwarrior->OneTimeAttack(bluewarrior, i_red);
if (attackResult(Time, Red, Blue)) return;
i_red++;
}
else {
i_red = 0;
if (redwarrior->Weaponptr[i_red]) {
redwarrior->OneTimeAttack(bluewarrior, i_red);
if (attackResult(Time, Red, Blue)) return;
i_red++;
}
}
}
}
}
int tie_counter = 0;//回合制攻击轮数
while (!tempFlag) {
redlife = redwarrior->Life;
bluelife = bluewarrior->Life;
if (bluewarrior->SumWeap) {
if (i_blue == bluewarrior->SumWeap) i_blue = 0;
if (bluewarrior->Weaponptr[i_blue]) {
bluewarrior->OneTimeAttack(redwarrior,i_blue);
if (attackResult(Time, Red, Blue)) return;
i_blue++;
}
else {
int i;
for (i = i_blue; i < bluewarrior->SumWeap; i++)
if (bluewarrior->Weaponptr[i]) break;
if (i < bluewarrior->SumWeap) {
i_blue = i;
bluewarrior->OneTimeAttack(redwarrior,i_blue);
if (attackResult(Time, Red, Blue)) return;
i_blue++;
}
else {
i_blue = 0;
if (bluewarrior->Weaponptr[i_blue]) {
bluewarrior->OneTimeAttack(redwarrior,i_blue);
if (attackResult(Time, Red, Blue)) return;
i_blue++;
}
}
}
}
if (redwarrior->SumWeap) {
if (i_red == redwarrior->SumWeap) i_red = 0;
if (redwarrior->Weaponptr[i_red]) {
redwarrior->OneTimeAttack(bluewarrior, i_red);
if (attackResult(Time, Red, Blue)) return;
i_red++;
}
else {
int i;
for (i = i_red; i < redwarrior->SumWeap; i++)
if (redwarrior->Weaponptr[i]) break;
if (i < redwarrior->SumWeap) {
i_red = i;
redwarrior->OneTimeAttack(bluewarrior, i_red);
if (attackResult(Time, Red, Blue)) return;
i_red++;
}
else {
i_red = 0;
if (redwarrior->Weaponptr[i_red]) {
redwarrior->OneTimeAttack(bluewarrior, i_red);
if (attackResult(Time, Red, Blue)) return;
i_red++;
}
}
}
}
if (redlife == redwarrior->Life && bluelife == bluewarrior->Life)
tie_counter++;
else
tie_counter = 0;
if (tie_counter >= 5)
tempFlag = 1;
}
if (tempFlag) {
redwarrior->ArrangeWeapon(); bluewarrior->ArrangeWeapon();//打完了也要记得排个序
//000:40 both red iceman 1 and blue lion 12 were alive in city 2
printf("%.3d:40 both red %s %d and blue %s %d were alive in city %d\n", Time, Warrior::WarriorName[redwarrior->OrderInMaking], redwarrior->OrderInTotal,
Warrior::WarriorName[bluewarrior->OrderInMaking], bluewarrior->OrderInTotal, Cityname);
if (redwarrior->OrderInMaking == DRAGON)
//003:40 blue dragon 2 yelled in city 4
printf("%.3d:40 red dragon %d yelled in city %d\n", Time, redwarrior->OrderInTotal, Cityname);
if (bluewarrior->OrderInMaking == DRAGON)
//003:40 blue dragon 2 yelled in city 4
printf("%.3d:40 blue dragon %d yelled in city %d\n", Time, bluewarrior->OrderInTotal, Cityname);
}
}
void Headquarter::HeadAnnounce(int Time)
{
// 000:50 120 elements in blue headquarter
char HeadquarterName[20];
GetColor(HeadquarterName);
printf("%.3d:50 %d elements in %s headquarter\n", Time, TotalLifeValue, HeadquarterName);
}
void Warrior::WarriorAnnounce(int Time)
{
//000:55 blue wolf 2 has 2 sword 3 bomb 0 arrow and 7 elements
char HeadquarterName[20];
pHeadquarter->GetColor(HeadquarterName);
printf("%.3d:55 %s %s %d has %d sword %d bomb %d arrow and %d elements\n", Time, HeadquarterName, Warrior::WarriorName[OrderInMaking], OrderInTotal,
NumOfWeapon[SWORD], NumOfWeapon[BOMB], NumOfWeapon[ARROW], Life);
}
char * Weapon::WeaponName[WEAPON_NUM] = {"sword","bomb","arrow" };
int Warrior::AttackForce[WARRIOR_NUM];
char * Warrior::WarriorName[WARRIOR_NUM] = {"dragon","ninja","iceman","lion","wolf"};
int Warrior::InitLifeValue[WARRIOR_NUM];
int Headquarter::MakingOrder[2][WARRIOR_NUM] = {{ 2,3,4,1,0 } ,{ 3,0,1,2,4 }};
bool Headquarter::MainFlag = 1;
int Lion::LoyaltyDecrease;
int main()
{
/*第一行是t,代表测试数据组数
每组样例共三行。
第一行,4个整数 M,N,K, T。其含义为:
每个司令部一开始都有M个生命元( 1 <= M <= 100000)
两个司令部之间一共有N个城市( 1 <= N <= 20 )
lion每前进一步,忠诚度就降低K。(0<=K<=100)
要求输出从0时0分开始,到时间T为止(包括T) 的所有事件。T以分钟为单位,0 <= T <= 6000
第二行:五个整数,依次是 dragon 、ninja、iceman、lion、wolf 的初始生命值。它们都大于0小于等于200
第三行:五个整数,依次是 dragon 、ninja、iceman、lion、wolf 的攻击力。它们都大于0小于等于200*/
int t;
scanf("%d", &t);
int Case = 1;
while (t--) {
printf("%d\n", Case++);
int lifeValue, CityNumber, TotalTime, Hour = 0; Headquarter::MainFlag = 1;
scanf("%d%d%d%d", &lifeValue, &CityNumber, &Lion::LoyaltyDecrease, &TotalTime);
for (int i = 0; i < WARRIOR_NUM; i++)
scanf("%d", &Warrior::InitLifeValue[i]);
for (int i = 0; i < WARRIOR_NUM; i++)
scanf("%d", &Warrior::AttackForce[i]);
Headquarter Red(0, lifeValue);
Headquarter Blue(1, lifeValue);
City *cities = new City[CityNumber+2];
for (int i = 0; i < CityNumber+2; ++i) {
cities[i].redwarrior = NULL;
cities[i].bluewarrior = NULL;
cities[i].Cityname = i;
cities[i].ishead = 0;
}
cities[0].ishead = 1;
cities[CityNumber+1].ishead = 1;
while (Hour * 60 <= TotalTime) {
if (!Red.Stop) {
Red.Produce(Hour);
if (!Red.Stop)//根据Produce()的写法,这里的两次判断是必须的
cities[0].RedInit(&Red);
}
if (!Blue.Stop) {
Blue.Produce(Hour);
if (!Blue.Stop)
cities[CityNumber+1].BlueInit(&Blue);
}
if (Hour * 60 + 5 <= TotalTime) {
for (int i = 0; i <= CityNumber + 1; ++i) {
if (cities[i].redwarrior ) {
if ( cities[i].redwarrior->WarriorKind() == 3 ) {
if (cities[i].redwarrior->LionEscape(Hour)) {
Red.DestroyWarrior(cities[i].redwarrior->WarriorOrderInTotal() - 1);
delete cities[i].redwarrior;
cities[i].redwarrior = NULL;
}
}
}
if (cities[i].bluewarrior ) {
if( cities[i].bluewarrior->WarriorKind() == 3 ) {
if (cities[i].bluewarrior->LionEscape(Hour)) {
Blue.DestroyWarrior(cities[i].bluewarrior->WarriorOrderInTotal() - 1);
delete cities[i].bluewarrior;
cities[i].bluewarrior = NULL;
}
}
}
}
}
if (Hour * 60 + 10 <= TotalTime) {
int shangxian = CityNumber + 1;
for (int i = shangxian; i > 0; i--) {
RedWarriorMove(&cities[i-1], &cities[i], Hour);
}
for (int i = 0; i < shangxian; i++) {
BlueWarriorMove(&cities[i+1], &cities[i], Hour);
}
if (!Headquarter::MainFlag) break;
}
if (Hour * 60 + 35 <= TotalTime) {
for (int i = 1; i < CityNumber+1; ++i) {
if (cities[i].redwarrior && cities[i].bluewarrior) {
cities[i].redwarrior->Rob(cities[i].bluewarrior, Hour);
cities[i].bluewarrior->Rob(cities[i].redwarrior, Hour);
}
}
}
if (Hour * 60 + 40 <= TotalTime) {
for (int i = 1; i < CityNumber+1; ++i)
cities[i].Battling(Hour, &Red, &Blue);
}
if (Hour * 60 + 50 <= TotalTime) {
Red.HeadAnnounce(Hour);
Blue.HeadAnnounce(Hour);
}
if (Hour * 60 + 55 <= TotalTime) {
for (int i = 1; i < CityNumber+1; ++i) {
if (cities[i].redwarrior) cities[i].redwarrior->WarriorAnnounce(Hour);
if (cities[i].bluewarrior) cities[i].bluewarrior->WarriorAnnounce(Hour);
}
}
Hour++;
}
}
return 0;
}