【Swift4】(5) 函数基本使用 | 可变参数 | inout引用传递 | 函数类型返回值 | 函数嵌套
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2024-03-17 16:18:04
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函数基本使用
关键字:func
func hello(name:String) ->String
{
let result = "Hello,"+name
return result
}
hello(name: "imagine")
可选型:
func hello(name:String?,greet:String) ->String
{
let result = greet+","+(name)!
return result
}
var nickname:String? //nil
nickname = "imagine"
hello(name: nickname,greet: "Good Night") //Good Night,imagine"
无参数函数,直接返回一个字符串类型的函数:
func sayHello() ->String
{
return "Welcome to imaginecode"
}
sayHello() //"Welcome to imaginecode"
空类型void / () ,不返回任何值
func sayVoid() ->Void{
print("it is a void func")
}
使用元组让函数返回多个值
func maxminScores( scores:[Int]) -> ( maxscore:Int,minscore:Int)? //元组的可选型
{
if scores.isEmpty{
return nil
}
var curmax = scores[0] ,curmin = scores[0]
for score in scores[1..<scores.count]{
curmax = max(curmax, score)
curmin = min(curmin, score)
}
return (curmax,curmin)
}
var scores:[Int]? = [12,60,71,81,91,100] //可选型数组
scores = scores ?? []
if let result = maxminScores(scores: scores!)
{
print(result.maxscore)
print(result.minscore)
}
内部参数名和外部参数名
func hello(userName nickname:String,greeting greet:String) -> String{ //内部参数nickname,greet,属于函数体
let result = greet+":"+nickname
return result
}
hello(userName: "imagine", greeting: "codeing") //给参数nickname与greet起了外部参数名userName和greeting
参数的默认值
func hello(nickname:String,greet:String = "hello") -> String{ //给greet默认值hello
let result = greet+":"+nickname
return result
}
hello(nickname: "imagine") //"hello:imagine"
func hello(nickname:String,greet:String = "hello",other:String = "nihao") -> String{ //给greet默认值hello
let result = greet+":"+nickname+other
return result
}
hello(nickname: "imagine",other:"how do you do") //"hello:imaginehow do you do"
可变参数
- 一个函数最好只能设置一个可变参数,并且该可变参数只能放在这个函数参数列表的最后一个位置
- 必须参数 > 默认值参数 > 可变参数
func add(a:Int,b:Int,others:Int ... ) ->Int //others是可变参数 ... 将其解析为数组
{
var result = a + b
for num in others
{
result += num
}
return result
}
var res = add(a: 2, b: 3)
res = add(a: 2, b: 3, others: 4,5,6)
NSLog(format: String, args: CVarArg...) //CvarArg也是可变参数
inout参数 - 引用传递
- inout用于声明数据是地址传递,也称之为引用传递;
- inout修饰的参数是不能有默认值的,有范围的参数集合也不能被修饰;
- 一个参数一旦被inout修饰,就不能再被var和let修饰了。
func swapTwoInts( a:inout Int,b:inout Int)
{
let t = a;
a = b
b = t
}
var x = 0, y = 100
swapTwoInts(a: &x, b: &y) //传入引用参数
函数类型
func add(a:Int,b:Int) -> Int
{
return a+b
}
let anotherAdd:(Int,Int)->Int = add //参数为两个Int,返回类型为Int ,add 作为变量
anotherAdd(3,4)
func changeScores1(scores:inout [Int]) {
for i in 0..<scores.count {
scores[i] = Int(sqrt(Double(scores[i]))*10)
}
}
func changeScores2(scores:inout [Int]) {
for i in 0..<scores.count {
scores[i] = Int(sqrt(Double(scores[i]))/150.0 * 100.0)
}
}
func changeScores3(scores:inout [Int]) {
for i in 0..<scores.count {
scores[i] += 3
}
}
var scores1 = [20,40,60,80,90]
changeScores1(scores: &scores1)
var scores2 = [20,40,60,80,90]
changeScores2(scores: &scores2)
var scores3 = [20,40,60,80,90]
changeScores3(scores: &scores3)
改进:
func changeScores(op:(Int)->Int, scores:inout [Int])
{
for i in 0..<scores.count{
scores[i] = op(scores[i])
}
}
func op1(x:Int)->Int {return Int(sqrt(Double(x))*10)}
func op2(x:Int)->Int {return Int(sqrt(Double(x))/150.0*100.0)}
func op3(x:Int)->Int {return x + 3}
var scores1 = [20,40,60,80,90]
changeScores(op: op1, scores: &scores1)
var scores2 = [20,40,60,80,90]
changeScores(op: op2, scores: &scores2)
var scores3 = [20,40,60,80,90]
changeScores(op: op3, scores: &scores3)
var arr = [Int]()
for _ in 1...20
{
arr.append(Int(arc4random()%100))
}
arr
func compareTwoInts(a:Int,b:Int) -> Bool{return a>b }
arr.sort()
返回函数类型的返回值、函数嵌套
//邮费计算
func mailcost1(weight:Int) -> Int
{
return 1*weight
}
func mailcost2(weight:Int) -> Int
{
return 2*weight
}
func chooseMailCostMethod(weight:Int) -> (Int)->Int //返回一个Int类型的函数,解耦作用
{
return weight <= 10 ? mailcost1 : mailcost2
}
func totalCost(price:Int,weight:Int) -> Int
{
let mailCost:(Int)->Int = chooseMailCostMethod(weight: weight)
return mailCost(weight) + price*weight
}
另一种写法:函数嵌套
func mailcost1(weight:Int) -> Int
{
return 1*weight
}
func mailcost2(weight:Int) -> Int
{
return 2*weight
}
func totalCost(price:Int,weight:Int) -> Int
{
func chooseMailCostMethod(weight:Int) -> (Int)->Int //函数嵌套
{
return weight <= 10 ? mailcost1 : mailcost2
}
let mailCost:(Int)->Int = chooseMailCostMethod(weight: weight)
return mailCost(weight) + price*weight
}
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