mssql sqlserver 获取数据表中一行中多列中列中的最小值的方法分享
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2024-03-15 21:26:00
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摘要:
下文讲述通过sql脚本获取一个数据表中,多列数据中最小列值数据的方法
实验环境:sqlserver 2008 R2
例:
当我们建立一张数据表存储三台设备生产一个同样工序所需的时间,
先我们需获取每次生产的最短时间
create table test
(name varchar(10),time1 int,time2 int,time3 int)
insert into test (name,time1,time2,time3)
values
('猫猫小屋',1,2,3), ('sql教程专用',8,9,6), ('c',11,22,8), ('d',101,201,38),
('e',6,7,9), ('maomao365',8,8,13), ('g',2,2,30), ('h',82,56,53)
go
---方法1:使用values子句构建临时表
select name,(select min(timeMin) from (values (time1),(time2),(time3)) as #temp(timeMin)) as timeMin from test
---方法2 行转列
select name, min(timeMin) as [最小数] from test unpivot (timeMin for timeMint in (time1,time2,time3)) as u group by name
--方法3:使用 union all组合新表
select name, (select min(timeMin)
as [最小数] from (
select test.time1 as timeMin
union all
select test.time2
union all
select test.time3) ud)
MaxDate from test
go
truncate table test
drop table test