Java中累计时间的计算(以小时为最终结果)

最近在项目中需要用到工作累计时间，所以就就写了一个小方法，作用是可以计算两个时间点之间的累积时间(即累积工作小时)，这里头需要注意的是输入的日期格式为

“yyyy-MM-dd-HH”，目前测试过后，可以计算不同年月日之间的小时差，下面附上主要代码：

public static int workHours(String startTime,String endTime){
		String[] startTimes = getStrings(startTime);
		for (int i = 0; i < startTimes.length; i++) {
			System.out.print(startTimes[i] + " ");
		}
		System.out.println();
		System.out.println("------------------------------");
		String[] endTimes = getStrings(endTime);
		for (int i = 0; i < endTimes.length; i++) {
			System.out.print(endTimes[i] + " ");
		}
		int workHours = 0;
		int workDays = 0;
		if (startTimes[0].equals(endTimes[0])) {// 年
			if (startTimes[1].equals(endTimes[1])) {// 月
				if (startTimes[2].equals(endTimes[2])) {// 同一天的不同小时
					workHours = Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
				} else {// 同一月不同的一天
					workDays = Integer.parseInt(endTimes[2]) - Integer.parseInt(startTimes[2]);
					workHours = workDays * 24 + Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
				}
			} else {// 同一年不同月
				String startMs = startTime.substring(0, 10);
				String endMs = endTime.substring(0, 10);
				Date earlydate = new Date();
				Date latedate = new Date();
				DateFormat df = DateFormat.getDateInstance();
				try {
					earlydate = df.parse(startMs);
					latedate = df.parse(endMs);
				} catch (ParseException e) {
					e.printStackTrace();
				}
				workDays = daysBetween(earlydate, latedate);
				workHours = workDays * 24 + Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
			}
		}else {//不同的年
			String startMs = startTime.substring(0, 10);
			String endMs = endTime.substring(0, 10);
			Date earlydate = new Date();
			Date latedate = new Date();
			DateFormat df = DateFormat.getDateInstance();
			try {
				earlydate = df.parse(startMs);
				latedate = df.parse(endMs);
			} catch (ParseException e) {
				e.printStackTrace();
			}
			workDays = differentDays(earlydate, latedate);
			workHours = workDays * 24 + Integer.parseInt(endTimes[3]) - Integer.parseInt(startTimes[3]);
		}
		System.out.println();
		System.out.println("------------------------------");
		System.out.println(workDays);
		System.out.println(workHours);
		return workHours;
	}

其中用到的两个方法如下：

public static String[] getStrings(String time) {
		String[] s = time.split("-");
		return s;
	}
	public static final int daysBetween(Date early, Date late) {
		java.util.Calendar calst = java.util.Calendar.getInstance();
		java.util.Calendar caled = java.util.Calendar.getInstance();
		calst.setTime(early);
		caled.setTime(late);
		// 设置时间为0时
		calst.set(java.util.Calendar.HOUR_OF_DAY, 0);
		calst.set(java.util.Calendar.MINUTE, 0);
		calst.set(java.util.Calendar.SECOND, 0);
		caled.set(java.util.Calendar.HOUR_OF_DAY, 0);
		caled.set(java.util.Calendar.MINUTE, 0);
		caled.set(java.util.Calendar.SECOND, 0);
		// 得到两个日期相差的天数
		int days = ((int) (caled.getTime().getTime() / 1000) - (int) (calst.getTime().getTime() / 1000)) / 3600 / 24;
		return days;
	}
	public static int differentDays(Date date1, Date date2) {
		Calendar calst = Calendar.getInstance();
		calst.setTime(date1);
		Calendar caled = Calendar.getInstance();
		caled.setTime(date2);
		int day1 = calst.get(Calendar.DAY_OF_YEAR);
		int day2 = caled.get(Calendar.DAY_OF_YEAR);
		int year1 = calst.get(Calendar.YEAR);
		int year2 = caled.get(Calendar.YEAR);
		calst.set(java.util.Calendar.HOUR_OF_DAY, 0);
		calst.set(java.util.Calendar.MINUTE, 0);
		calst.set(java.util.Calendar.SECOND, 0);
		caled.set(java.util.Calendar.HOUR_OF_DAY, 0);
		caled.set(java.util.Calendar.MINUTE, 0);
		caled.set(java.util.Calendar.SECOND, 0);
		if (year1 != year2) // 同一年
		{
			int timeDistance = 0;
			for (int i = year1; i < year2; i++) {
				if (i % 4 == 0 && i % 100 != 0 || i % 400 == 0) {// 闰年
					timeDistance += 366;
				} else {// 不是闰年
					timeDistance += 365;
				}
			}
			return timeDistance + (day2 - day1);
		} else {// 不同年
			System.out.println("判断day2 - day1 : " + (day2 - day1));
			return day2 - day1;
		}
	}