代码分析Java中线程的等待与唤醒
程序员文章站
2024-03-06 22:38:44
我们先来看一下实例代码:
class threada extends thread{
public threada(string name) {...
我们先来看一下实例代码:
class threada extends thread{ public threada(string name) { super(name); } public void run() { synchronized (this) { system.out.println(thread.currentthread().getname()+" call notify()"); notify(); } } } public class waittest { public static void main(string[] args) { threada t1 = new threada("t1"); synchronized(t1) { try { // 启动“线程t1” system.out.println(thread.currentthread().getname()+" start t1"); t1.start(); // 主线程等待t1通过notify()唤醒。 system.out.println(thread.currentthread().getname()+" wait()"); t1.wait(); system.out.println(thread.currentthread().getname()+" continue"); } catch (interruptedexception e) { e.printstacktrace(); } } } }
输出结果:main start t1 -> main wait() -> t1 call notify() -> main continue
其实调用t1.start(),t1为就绪状态,只是main方法中,t1被main线程锁住了,t1.wait()的时候,让当前线程等待,其实是让main线程等待了,然后释放了t1锁,t1线程执行,打印t1 call notify(),然后唤醒main线程,最后结束;
这里说一下wait()与sleep()的区别,他们的共同点都是让线程休眠,但是wait()会释放对象同步锁,而sleep()不会;下面的代码t1结束之后才会运行t2;能够证实这一点;
public class sleeplocktest{ private static object obj = new object(); public static void main(string[] args){ threada t1 = new threada("t1"); threada t2 = new threada("t2"); t1.start(); t2.start(); } static class threada extends thread{ public threada(string name){ super(name); } public void run(){ synchronized (obj) { try { for(int i=0; i <10; i++){ system.out.printf("%s: %d\n", this.getname(), i); // i能被4整除时,休眠100毫秒 if (i%4 == 0) thread.sleep(100); } } catch (interruptedexception e) { e.printstacktrace(); } } } } }