1.前台ajax数据提交
<form id="login_form" action="" method="post">
<div class="login_frame" style="position:relative";>
<div class="login_gl" style="margin-top:35px;">
<span class="login_wz" >后台管理系统</span>
</div>
<div class="login_user">
<input id="username" name="username" type="text" placeholder="请输入您的用户名" value="" style="width:100%;height:32px;border-style:none;font-size:16px;color:#959595;"/>
</div>
<div class="login_user">
<input id="password" name="password" type="password" placeholder="请输入您的密码" value="" style="width:100%;height:32px;border-style:none;font-size:16px;color:#959595;"/>
</div>
<div id="login_btn" class="login_log">
<span style="font-size:16px;">登录</span>
</div>
</div>
</form>
</div>
<script type="text/javascript">
$("#login_btn").click(function(){
var username = $.trim($("#username").val());
var password = $.trim($("#password").val());
if(username == ""){
alert("请输入用户名");
return false;
}else if(password == ""){
alert("请输入密码");
return false;
}
//ajax去服务器端校验
var data= {username:username,password:password};
$.ajax({
type:"post",
url:"__controller__/check_login",
data:data,
datatype:'json',
success:function(msg){
//alert(msg);
if(msg==1){
window.location.href = "{:u('index/personal')}";
}else{
alert("登录失败,请重试!");
}
}
});
});
</script>
2.后台校验:
* */
public function check_login(){
$password=i('param.password');
$username=i('param.username');
$data["name"]=$username;
$user=m('systemuser');
$list=$user->where($data)->find();
$return=0;
if($list!=""){
if($list['password']==md5($password) && $list['status'] == 1){
//登录时间和登录ip
$public = new publiccontroller();
$lastlogonip=$public->ip_address();
$time=$time=date("y-m-d h:i:s", time());
$where=array('id'=>$list['id']);
$user->where($where)->save(array('lastlogonip'=>$lastlogonip,'lastlogontime'=>$time));
$this->login($list);
$return=1;//登录成功
}
}else{
$return=2;//登录失败
}
$this->ajaxreturn($return);
}
以上就是本文的全部内容,希望本文的内容对大家的学习或者工作能带来一定的帮助,同时也希望多多支持!