Leetcode 344: 反转字符串
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2024-03-04 16:54:23
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题目描述:
编写一个函数,其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
不要给另外的数组分配额外的空间,你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
示例 1:
输入:["h","e","l","l","o"]
输出:["o","l","l","e","h"]
示例 2:
输入:["H","a","n","n","a","h"]
输出:["h","a","n","n","a","H"]
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/reverse-string
思路:双指针+交换
/**
* @param {character[]} s
* @return {void} Do not return anything, modify s in-place instead.
*/
var reverseString = function(s) {
let left = 0, right = s.length - 1;
while(left <= right) {
[s[left], s[right]] = [s[right], s[left]];
left++;
right--;
}
};
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